PLS HELP ASAP! 10 POINTS!!

Mathematics

1 answer:

Ivenika [448]3 years ago

5 0

Answer:

length = 4 width = 4 height = 10

Step-by-step explanation:

8x4x5 = 160

4x4x10 = 160

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practice the flute for 45 then ate a snack for 15 minutes watched television for 30 minutes until 6:00 pm what time did she star

Katarina [22]

6:00-30 minutes is 5:30
5:30-15 minutes is 5:15
5:15-45 minutes is 4:30
She started on 4:30 pm

3 0

4 years ago

Can someone please help me with the circled one?

mezya [45]

They would be 10 and 1/2

Multiplying by 1/2 is basically dividing by 2, so 10 times 1/2 would be 10 divided by 2, which is 5

10 + 1/2 is also 10 1/2

8 0

4 years ago

I forgot how to do this.... can somebody help?

slamgirl [31]

$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\

\begin{array}{rllll} 
% left side templates
f(x)=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
y=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
f(x)=&{{ A}}\sqrt{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}}(\mathbb{R})^{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}} sin\left({{ B }}x+{{ C}} \right)+{{ D}}
\end{array}

$

$\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks horizontally by } {{ A}}\cdot {{ B}}\\\\
\bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}
\\\\
\bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\
\end{array}$

$\bf \begin{array}{llll}


\bullet \textit{ vertical shift by }{{ D}}\\
\qquad if\ {{ D}}\textit{ is negative, downwards}\\\\
\qquad if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{ B}}}
\end{array}$

now, with that template in mind, let's see

3 units to the right, that means C/B = -3 so hmm C = -3 and B = 1 will do, -3/1 = -3

vertical stretch by 2, so A = 2
reflected over the x-axis, so that means is flipped upside-down, so A = -2 then

and shifted down by 3, do D = -3

$\bf f(x)={{ A}}(\mathbb{R})^{{{ B}}x+{{ C}}}+{{ D}}\implies f(x)={{ -2}}(\mathbb{R})^{{{ 1}}x-{{ 3}}}-{{3}}\\\\\\ f(x)={{ -2}}(3)^{{{ }}x-{{ 3}}}-{{3}}$

3 0

4 years ago

E= n^2 + n +5 if n =3

zmey [24]

Answer:

Step-by-step explanation:

Putting value of n = 3 in equation

(3)2 + 3 + 5

9 + 8

= 17

3 0

3 years ago