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Neporo4naja [7]
3 years ago
13

Please help me with number #3 and check if the others are correct please I really need help

Mathematics
1 answer:
Sveta_85 [38]3 years ago
6 0
All I can say is 1 and 2 are correct.
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HELP ME SOLVE THESE PLEASE
Fittoniya [83]

Answer:

True

Step-by-step explanation:

An input is always anything that equals a sum.

Input: Small-Medium-Large

Output: Prices

7 0
3 years ago
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Which of the following sets of inequalities​
Ludmilka [50]

Inequalities help us to compare two unequal expressions. The correct options are 2 and 3.

<h3>What are inequalities?</h3>

Inequalities help us to compare two unequal expressions. Also, it helps us to compare the non-equal expressions so that an equation can be formed. It is mostly denoted by the symbol <, >, ≤, and ≥.

The inequality for the red portion is,

slope, m = (-2/-4) = 1/2

y-intercept is 2.

y ≤ (1/2)x + 2

The inequality for the blue portion is,
slope, m = (5-0)/(3-0.5) = 2

y-intercept is -1.

y > 2x - 1

Hence, the correct options are 2 and 3.

Learn more about Inequality:

brainly.com/question/19491153

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7 0
2 years ago
Differentiating a Logarithmic Function in Exercise, find the derivative of the function. See Examples 1, 2, 3, and 4.
Leni [432]

Answer:  \dfrac{2x^2-1}{x(x^2-1)}

Step-by-step explanation:

The given function : y=\ln(x(x^2 - 1)^{\frac{1}{2}})

\Rightarrow\ y=\ln x+\ln (x^2-1)^{\frac{1}{2}}    [\because \ln(ab)=\ln a +\ln b]

\Rightarrow y=\ln x+\dfrac{1}{2}\ln (x^2-1)}  [\because \ln(a)^n=n\ln a]

Now , Differentiate both sides  with respect to x , we will get

\dfrac{dy}{dx}=\dfrac{1}{x}+\dfrac{1}{2}(\dfrac{1}{x^2-1})\dfrac{d}{dx}(x^2-1) (By Chain rule)

[Note : \dfrac{d}{dx}(\ln x)=\dfrac{1}{x}]

\dfrac{1}{x}+\dfrac{1}{2}(\dfrac{1}{x^2-1})(2x-0)

[ \because \dfrac{d}{dx}(x^n)=nx^{n-1}]

=\dfrac{1}{x}+\dfrac{1}{2}(\dfrac{1}{x^2-1})(2x) = \dfrac{1}{x}+\dfrac{x}{x^2-1}\\\\\\=\dfrac{(x^2-1)+(x^2)}{x(x^2-1)}\\\\\\=\dfrac{2x^2-1}{x(x^2-1)}

Hence, the derivative of the given function is \dfrac{2x^2-1}{x(x^2-1)} .

8 0
3 years ago
Can you help me with my work
Pachacha [2.7K]
h(0)=3

The diver begins 3 meters above the water

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\begin{gathered} h(1)=8 \\ 8>6.75>3 \end{gathered}

The diver reaches a maximum height of 8ft

The

3 0
1 year ago
Which graph represents as a function of length of the trip
Sav [38]
Do you have a picture to go with it?
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