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Jlenok [28]
3 years ago
12

The school is using a bus to go on a field trip. The bus has 40 seats that each fit 2 people. How many busses would be needed to

transport 560 students?
Mathematics
2 answers:
Liula [17]3 years ago
6 0

Answer: They need 7 buses

Step-by-step explanation:

40 x 2 =80 560 divided by 80 =7

Kamila [148]3 years ago
5 0

Answer: 7 buses

Step-by-step explanation:

hope this helps!

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In the triangle below, determine the value of a.
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Read 2 more answers
Suppose 3% of the people contacted by phone are receptive to a certain sales pitch and buy your product. If your sales staff con
Shalnov [3]

Answer:

0% probability that more than 100 of the people contacted will purchase your product

Step-by-step explanation:

To solve this question, i am going to use the binomial approximation to the normal.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

p = 0.03, n = 2000

So

\mu = E(X) = np = 2000*0.03 = 60

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{2000*0.03*0.97} = 7.63

What is the probability that more than 100 of the people contacted will purchase your product?

This is 1 subtracted by the pvalue of Z when X = 100. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{100 - 60}{7.63}

Z = 5.24

Z = 5.24 has a pvalue of 1

1 - 1 = 0

0% probability that more than 100 of the people contacted will purchase your product

3 0
3 years ago
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