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3 years ago

Question 5 of 10

Mathematics

1 answer:

DochEvi [55]3 years ago

7 0

Answer:

False

Rise is the vertical change not the horizontal

Step-by-step explanation:

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I need help with both of these questions.

grigory [225]

Answer:

1) b=14.34 units.

2) a=20.48 units

Step-by-step explanation:

since, the triangle is a right angled triangle so we can use the trignometric identity in order to find the values of a and b.

let the base be denoted by 'B'.

height or perpendicular side of the triangle be denoted by 'P'.

and hypotenuse of the triangle be denoted by 'H'.

then using sine and cosine trignometric identity we have:

$\sin x=\dfrac{P}{H}$

and $\cos x=\dfrac{B}{H}$

Here x=35°

and H=25 units , P=b and B=a

Hence $\sin 35=\dfrac{b}{25}$

as $\sin 35=0.573576$

hence, b=14.3394 units.

also $\cos35=\dfrac{a}{25}$

and $\cos35=0.819152$

Hence a=20.4788 units

In two decimal places we could represent it as:

a=20.48 units

and b=14.34 units.

6 0

3 years ago

Please help!! Double points! write the ratios for sin X and cos X (Image attached)

Orlov [11]

Answer:

The ratio for sin(X) is $\frac{\sqrt{119} }{12}$

The ratio for cos(X) is $\frac{5}{12}$

Step-by-step explanation:

- The ratio of the sine of a right triangle is:

$sin(\alpha)=\frac{opposite-side}{hypotenuse}$

Since we need the ratio for angle X, $\alpha =X$ . From the picture we can infer that the opposite side of X is $\sqrt{119}$ . The hypotenuse (the side opposite to the right angle) is 12, so replacing the values:

$sin(X)=\frac{\sqrt{119} }{12}$

- The ratio of the cosine is:

$cos(\alpha)=\frac{adjacent-side}{hypotenuse}$

Similarly, $\alpha =X$ , adjacent side = 5, and hypotenuse = 12, so

$cos(X)=\frac{5}{12}$

6 0

4 years ago

Read 2 more answers

Tell whether a triangle can have sides with the

Dmitry [639]

Answer:

$3x+2 \ne x^2 \ne 2x$ for $x = 4$

Step-by-step explanation:

Given

Shape: Triangle

Dimension: 3x + 2, x^2 and 2x

$x = 4$

Required

Determine if it has equal sides

To do this, we simply substitute 4 for x in the given dimensions

3x + 2

$3x + 2 = 3 * 4 + 2$

$3x + 2 = 12 + 2$

$3x + 2 = 14$

x^2

$x^2 = 4^2$

$x^2 = 16$

2x

$2x = 2 * 4$

$2x = 8$

$3x+2 \ne x^2 \ne 2x$ for $x = 4$

8 0

3 years ago

Meera is a high school student who is going to work two jobs this summer

lilavasa [31]

Answer:

good for Meera

Step-by-step explanation:

but what is the question?????

5 0

4 years ago

Identify the slope and y-intercept of the equation. y = -2x + 1

Liula [17]

Answer:

Slope= -2 y intercept= 1

Step-by-step explanation:

PUT ME THE BRAINLIEST PLEASE

7 0

3 years ago