Answer:
I believe the answer is number 3.
Step-by-step explanation:
Well, <T+<S will equal 11x +2
so the equation will be 5x+10 + 58 = 11x +2
5x + 68 = 11x +2
66 = 6x (subtract 2, subtract 5x)
x = 11 (division)
To check,
<T = 5 (11) +10
<T = 65
11(11)+2 = 123
<T+<S = 123
65+58 = 123
Formula for distance between two points:
d = √((x₂-x₁)² + (y₂-y₁)²)
Let point 1 be (-3, 11) and point 2 be (5, 5)
Therefore x₁ = -3, y₁ = 11, x₂ =5, y₂ = 5, and substituting in the formula above.
d = √((x₂-x₁)² + (y₂-y₁)²)
= √((5- -3)² + (5-11)²)
= √((5+3)² + (5-11)²)
= √((8)² + (-6)²) 8² = 8*8 = 64, (-6)² = -6*-6 = 36
= √(64 + 36)
= √(100)
= 10
Distance = 10 units.
