If you want to describe the mass of the water in the pool,
then you'll express it in kilograms.
If you want to describe the volume of the water in the pool,
then you'll express it in Liters.
(Those two numbers will be pretty close to equal.)
I'd suggest you get rid of the fraction first. Mult. every term by 3. You will get
3y^2 + 10y + 3 = 0
From inspection, with coefficient a=3 and coeff. c = 3, the binomial factors could possibly begin with y or 3y: for example, y+1; also, the binom. factors may end in +1. Let's try the possible binomial factor 3y + 1.
Note that 10y separates into 9y+1y.
Then 3y^2 + 10y + 3 = 0 becomes
3y^2 + 9y + 1y + 3 = 0
Let's apply factoring by grouping:
3y^2 + 9y + 1y + 3 = 0
3y*(y + 3) + 1(y + 3) so y+3 is indeed a common factor.
Factoring y+3 out, we get (y+3)(3y + 1), which prove to be the correct set of factors. Multiply these together to ensure that the product is indeed y^2 + (10/3)y + 1.
Answer:
what do you mean by mutuals mate?
Step-by-step explanation:
Answer:
A, the first choice
Step-by-step explanation:
-3/4 2
1/7 -1 2/3
