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-Dominant- [34]
3 years ago
7

Can someone plzzz show me how to solve this?

Mathematics
1 answer:
Sliva [168]3 years ago
5 0

I wrote it down on paper, hope this is helpful.

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The function y = 8.5(1.1)x models the population in thousands of a town where x is the number of years after 2000. What will be
nikdorinn [45]

Answer:

The population will be at 65.45 in 2007.

Step-by-step explanation:

I graphed the equation below to find the answer.

If this answer is correct, please make me Brainliest!

6 0
3 years ago
What is a solid figure with two congruent parallel polygonal bases?
nika2105 [10]

A solid figure that has two congruent, parallel polygons as its bases would be a prism, and its sides are parallelograms.

3 0
3 years ago
A square ceiling has an area of 360 square feet. Alex wants to put molding around the entire perimeter of the ceiling. Approxima
Blababa [14]

Answer:

Option C is correct

76 feet

Step-by-step explanation:

Area of square(A) is given by:

A =s^2

where, s is the side of the square.

As per the statement:

A square ceiling has an area of 360 square feet.

⇒A = 360 square feet.

then;

s^2 = 360

⇒s = \sqrt{360} =18.973666

Perimeter(P) of square is given by:

P = 4s

then;

P = 4 \cdot 18.973666 = 75.894664 \approx 76 ft

Therefore, 76 feet molding does he need.

7 0
3 years ago
Jensen Tire & Auto is in the process of deciding whether to purchase a maintenance contract for its new computer wheel align
sasho [114]

Answer:

Step-by-step explanation:

Hello!

The given data corresponds to the variables

Y:  Annual Maintenance  Expense ($100s)

X: Weekly Usage  (hours)

n= 10

∑X= 253; ∑X²= 7347; \frac{}{X}= ∑X/n= 253/10= 25.3 Hours

∑Y= 346.50; ∑Y²= 13010.75; \frac{}{Y}= ∑Y/n= 346.50/10= 34.65 $100s

∑XY= 9668.5

a)

To estimate the slope and y-intercept you have to apply the following formulas:

b= \frac{sumXY-\frac{(sumX)(sumY)}{n} }{sumX^2-\frac{(sumX)^2}{n} } = \frac{9668.5-\frac{253*346.5}{10} }{7347-\frac{(253)^2}{10} }= 0.95

a= \frac{}{Y} -b\frac{}{X} = 34.65-0.95*25.3= 10.53

^Y= a + bX

^Y= 10.53 + 0.95X

b)

H₀: β = 0

H₁: β ≠ 0

α:0.05

F= \frac{MS_{Reg}}{MS_{Error}} ~~F_{Df_{Reg}; Df_{Error}}

F= 47.62

p-value: 0.0001

To decide using the p-value you have to compare it against the level of significance:

If p-value ≤ α, reject the null hypothesis.

If p-value > α, do not reject the null hypothesis.

The decision is to reject the null hypothesis.

At a 5% significance level you can conclude that the average annual maintenance expense of the computer wheel alignment and balancing machine is modified when the weekly usage increases one hour.

b= 0.95 $100s/hours is the variation of the estimated average annual maintenance expense of the computer wheel alignment and balancing machine is modified when the weekly usage increases one hour.

a= 10.53 $ 100s is the value of the average annual maintenance expense of the computer wheel alignment and balancing machine when the weekly usage is zero.

c)

The value that determines the % of the variability of the dependent variable that is explained by the response variable is the coefficient of determination. You can calculate it manually using the formula:

R^2 = \frac{b^2[sumX^2-\frac{(sumX)^2}{n} ]}{[sumY^2-\frac{(sumY)^2}{n} ]} = \frac{0.95^2[7347-\frac{(253)^2}{10} ]}{[13010.75-\frac{(346.50)^2}{10} ]} = 0.86

This means that 86% of the variability of the annual maintenance expense of the computer wheel alignment and balancing machine is explained by the weekly usage under the estimated model ^Y= 10.53 + 0.95X

d)

Without usage, you'd expect the annual maintenance expense to be $1053

If used 100 hours weekly the expected maintenance expense will be 10.53+0.95*100= 105.53 $100s⇒ $10553

If used 1000 hours weekly the expected maintenance expense will be $96053

It is recommendable to purchase the contract only if the weekly usage of the computer is greater than 100 hours weekly.

4 0
2 years ago
If contact lenses cost 80$ how much will they cost if they are with 10% off?
nevsk [136]

10% of 80 = 8

80 - 8 = 72

if they are 10% off, the contact lenses will cost $72

6 0
2 years ago
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