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3 years ago

The figure shows a rectangle ABCD.

Mathematics

2 answers:

Basile [38]3 years ago

8 0

Answer:

39° is the required answer.

Step-by-step explanation:

BAD = 90°

ADE = 51°

AED = 180° - (BAD + ADE)

→ 180° - (90° + 51°)

→ 180° - 141° = 39°

finlep [7]3 years ago

3 0

Answer:

Answer:

The answer is 39°

Step-by-step explanation:

BAD = 90°

ADE = 51°

AED = 180° - BAD + ADE = 180° - 90° + 51°

= 39°

39° is the Final answer

#AnswerforTrees

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T is the midpoint of AE. AT=4x-3 and TE= 2x+7, find the length of AE

iris [78.8K]

If T is the midpoint, then that means its exactly 1/2 of the way between 2 points

this means we can set the 2 given values equal

4x - 3 = 2x + 7

first move like terms to the same side

2x = 10

x = 5

now that we know the length of x, we plug it back in to get the length

4x - 3 + 2x + 7 = 6x + 4

6(5) + 4 = 34

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3 years ago

Figure AAA is a scale image of figure BBB.

Elan Coil [88]

Answer:

Step-by-step explanation:

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3 years ago

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In Argentina, a cow on a ranch is expected to need an average of 4200 m2

nika2105 [10]

The cows of Argentina needs an approximate area of 4200 m² for grazing, and there is a total of 4500 cows.

And we are asked to find the total area of their grazing but in hectares. So, we can write:

$1 \: cow = 4200 \: {m}^{2}$

Then, for 4500 cows:

$4500 \: cows = 4200 \: {m}^{2} \times 4500$

$4500 \: cows = 18900000 \: m {}^{2}$

We know that, 1 hectares = 10000 m² = 10⁴ m²

Then let the area of the field be x in hectares:

$1 \: hectare = 10000 \: {m}^{2}$

$x \: hectare = 18900000 \: {m}^{2}$

Then, putting them in proportion, We will get:

$x = \dfrac{18900000}{10000} hectares$

$x = \boxed{ 1890 \: hectares}$

So, the total area in hectares = 1890 hectares.

And we are done !!

#CarryOnLearning

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6 0

3 years ago

If the divisor is 40 what is the least three-digit dividend tag would give a remainder of 4

fgiga [73]

Let the three digit dividend be abc ,

then abc = 40*Q+4

So, abc is "40 times Q (the quotient, a number) plus 4"

we try a few values of Q for which 40Q+4 is a 3 digit number:

for Q=2

40*2+4=80+4=84

for Q=3

40*3+4=120+4=124

Answer: 124

4 0

3 years ago

If you are dealt 5 cards at random from a standard deck of playing cards, what is the probability that at most 4 of them are spa

alexira [117]

Answer:

Step-by-step explanation:

No of ways in which 5 cards are chosen is $N=^{52}C_5$

No of ways in which at most 4 cards are spades $N_0=$ Total ways-5 spades

$=^{52}C_5-^{13}C_5$

Probability that at most 4 cards are spade $P=\frac{N_0}{N}$

$P=\frac{^{52}C_5-^{13}C_5}{^{52}C_5}$

$P=\frac{2598960-1287}{2598960}$

$P=\frac{2597673}{2598960}=0.9995$

3 0

3 years ago