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erastova [34]
3 years ago
10

What is the answer to this image

Mathematics
1 answer:
polet [3.4K]3 years ago
3 0
27 square units is the answer
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How do you evaluate 3f(2)
d1i1m1o1n [39]

The answer should be 6f. You multiply the 3 and the 2 and then put the f at the end (:

5 0
3 years ago
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Tim has read 40% of a book. He has 42 more pages to finish. How many pages are there in the book?
suter [353]

Answer:

66 pages

Step-by-step explanation:

I think that is the answer hope it helps you.

8 0
3 years ago
HELP I NEED HELP ASAP HELP I NEED HELP ASAP HELP I NEED HELP ASAP HELP I NEED HELP ASAP
Katena32 [7]

Answer:

The equation is ;

4x - y = 13

Step-by-step explanation:

The general equation of a straight line is;

y = mx + b

where m is the slope and b is the y-intercept

from what we are given, let us write the second equation in the general form

x + 4y = 10

4y = -x + 20

y = -1/4x + 20/4

y = -1/4x + 5

mathematically, when two lines are perpendicular, the product of their slope is -1

So for the second line with slope m2

m2 * -1/4 = -1

m2 = 4

So, using the general form, we have the equation as;

y = 4x + b

To get the value of b, we substitute the coordinates of the given point (3,-1)

-1 = 4(3) + b

-1 = 12 + b

b = -1-12

b = -13

So the equation is;

y = 4x - 13 which can be rewritten as;

4x-y = 13

6 0
3 years ago
Que numero es mayor 0.086 o 86%​
Misha Larkins [42]

Answer:86% es mas

Step-by-step explanation:

86% es lo mismo que 0.86 y eso es mayor que 0.086

6 0
3 years ago
Graph the image of this figure after a dilation with a scale factor of 12 centered at the point (2, 2) . Use the polygon tool to
Alla [95]

Answer:

Labelled the given figure triangle as A, B and C.

In triangle ABC;

The coordinates of ABC are:

A = (0, 4)

B = (-2, 10) and

C = (-6, 8)

To find the image of this figure after a dilation with a scale factor of \frac{1}{2} centered at the point O=(2, 2).

The rule of dilation with scale factor \frac{1}{2} centered at the point (2, 2) is given by;

(x, y) \rightarrow (\frac{1}{2}(x-2) +2 , \frac{1}{2}(y-2) +2)

or

(x, y) \rightarrow (\frac{1}{2}x+1 , \frac{1}{2}y+1)

The coordinate of the image of the figure after dilation are;

A(0, 4) \rightarrow A'(\frac{1}{2}(0)+1 , \frac{1}{2}(4)+1) = A'(1, 3)

B(-2, 10) \rightarrow B'(\frac{1}{2}(-2)+1 , \frac{1}{2}(10)+1) = B'(0, 6)

C(-6, 8) \rightarrow C'(\frac{1}{2}(-6)+1 , \frac{1}{2}(8)+1) = C'(-2, 5)

You can see the graph as shown below in the attachment:





5 0
3 years ago
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