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tensa zangetsu [6.8K]

2 years ago

9

Which set of ordered pairs represents y as a function of x?

2 answers:

ella [17]2 years ago

6 0

Answer:

b

Step-by-step explanation:

Aloiza [94]2 years ago

4 0

B

(0,0)(1,1)(1'0)(2,1)

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Marcus changed jobs after college. His old salary was $48000 per year. Now his new salary is 37% more per year. What is his new

spayn [35]

Answer:

65,760

Step-by-step explanation:

move decimal over two places to make a percent a decimal so .37

then multiply that times the 48000 to get 17,760 and then add that to the original 48000 to get 65,760

8 0

2 years ago

At a restaurant, you order a meal that costs $8. you leave a 15% tip. the sales tax is 6%. what is the total cost of the meal?

Oksi-84 [34.3K]

Easy! multiply the 6% by $8 then add it to the $8, now, multiply the 15% by the total of the cost with tax. then you all that to the total. ($9.75)

8 0

2 years ago

A simple random sample of items resulted in a sample mean of . The population standard deviation is . a. Compute the confidence

Varvara68 [4.7K]

Answer:

(a): The 95% confidence interval is (46.4, 53.6)

(b): The 95% confidence interval is (47.9, 52.1)

(c): Larger sample gives a smaller margin of error.

Step-by-step explanation:

Given

$n = 30$ -- sample size

$\bar x = 50$ -- sample mean

$\sigma = 10$ --- sample standard deviation

Solving (a): The confidence interval of the population mean

Calculate the standard error

$\sigma_x = \frac{\sigma}{\sqrt n}$

$\sigma_x = \frac{10}{\sqrt {30}}$

$\sigma_x = \frac{10}{5.478}$

$\sigma_x = 1.825$

The 95% confidence interval for the z value is:

$z = 1.960$

Calculate margin of error (E)

$E = z * \sigma_x$

$E = 1.960 * 1.825$

$E = 3.577$

The confidence bound is:

$Lower = \bar x - E$

$Lower = 50 - 3.577$

$Lower = 46.423$

$Lower = 46.4$ --- approximated

$Upper = \bar x + E$

$Upper = 50 + 3.577$

$Upper = 53.577$

$Upper = 53.6$ --- approximated

<em>So, the 95% confidence interval is (46.4, 53.6)</em>

Solving (b): The confidence interval of the population mean if mean = 90

First, calculate the standard error of the mean

$\sigma_x = \frac{\sigma}{\sqrt n}$

$\sigma_x = \frac{10}{\sqrt {90}}$

$\sigma_x = \frac{10}{9.49}$

$\sigma_x = 1.054$

The 95% confidence interval for the z value is:

$z = 1.960$

Calculate margin of error (E)

$E = z * \sigma_x$

$E = 1.960 * 1.054$

$E = 2.06584$

The confidence bound is:

$Lower = \bar x - E$

$Lower = 50 - 2.06584$

$Lower = 47.93416$

$Lower = 47.9$ --- approximated

$Upper = \bar x + E$

$Upper = 50 + 2.06584$

$Upper = 52.06584$

$Upper = 52.1$ --- approximated

<em>So, the 95% confidence interval is (47.9, 52.1)</em>

Solving (c): Effect of larger sample size on margin of error

In (a), we have:

$n = 30$ $E = 3.577$

In (b), we have:

$n = 90$ $E = 2.06584$

<em>Notice that the margin of error decreases when the sample size increases.</em>

4 0

2 years ago

F the simple interest on $4000 for 6 years is $1440, then what is the interest rate?

Alborosie

Answer:

Step-by-step explanation:

$rate=\frac{interest \times 100}{principle \times time } \\=\frac{1440 \times 100}{4000 \times 6 } \\=6 \%$

7 0

2 years ago

How to write three hundred million twenty two thousand

Vlad [161]

This is the way you write 300,022,000

8 0

2 years ago