It has to be wider than the first two arcs or else you will just get two circles side by side with point c in common. I usually measure it to be the length of a point between the c and j. It is a good point to get the arcs to intersect.
Answer:
32
Step-by-step explanation:
n(A∪B)=n(A)+n(B)−n(A∩B)−−−−−−−(1)
Given n(A)= ? we represent with x
n(B)= 16
n(A∪B) = 32
Substituting in equation 1 to get n(A)
32 = n(A) + 9 − 9
⇒n(A) = 32 − 0
n(A) = 32
to confirm this we put the values into the formula below
n(A∪B)=n(A)+n(B)−n(A∩B)−−−−−−−(1)
32 = 32 + 9 - 9
Answer:
A
Step-by-step explanation:
Suppose x is odd. Then x^4 is also odd. So x^4 + 1 is even. Then for the whole function to be even, kx^2 should also be even. x^2 is obviously odd as x is odd. So to make kx^2 even, k should be even.
Now suppose x is <em>even</em>. Then x^4 + 1 is odd. So to make the function even, kx^2 should also be odd. But x is even, so kx^2 automatically becomes even, and then the whole function becomes odd. So the student's statement doesn't hold when x is even, no matter what the value of k is.
So the statement is true when x is odd and k is even.
Hope it helps and if it does, plzzzz mark me brainliest...
Answer:
x = 50
y = 10
Explanation:
When two lines intersect, four angles are formed. A theorem states that each two vertically opposite angles are equal.
Applying this on the given, we would find that:
1) 3y and x-20 are vertically opposite angles. This means that:
3y = x - 20
This can be rewritten as:
x = 3y + 20 ........> equation I
2) y+140 and 5x-100 are vertically opposite angles. This means that:
y + 140 = 5x - 100 ..............> equation II
Substitute with I in II and solve for y as follows:
y + 140 = 5x - 100
y + 140 = 5(3y+20) - 100
y + 140 = 15y + 100 - 100
15y - y = 140
14y = 140
y = 10
Substitute with the value of y in equation I to get x as follows:
x = 3y + 20
x = 3(14) + 20
x = 50
Hope this helps :)
