<h3>
Answer: 864</h3>
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Work Shown:
There are,
- 3 sizes of coffee
- 4 types of coffee
- 2 choices for cream (you pick it or you leave it out)
- 2 choices for sugar (same idea as the cream)
This means there are 3*4*2*2 = 12*4 = 48 different coffees. We'll use this value later, so let A = 48.
There are 6 bagel options. Also, there are 3 choices in terms of if you order the bagel plain, with butter, or with cream cheese. This leads to 6*3 = 18 different ways to order a bagel. Let B = 18.
Multiply the values of A and B to get the final answer
A*B = 48*18 = 864
There are 864 ways to order a coffee and bagel at this restaurant.
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If you're curious why you multiply the values out, consider this smaller example.
Let's say you had 3 choices of coffee and 2 choices for a bagel. Form a table with 3 rows and 2 columns. Place the different coffee choices along the left to form each row. Along the top, we'll have the two different bagel choices (one for each column).
This 3 by 2 table leads to 3*2 = 6 individual table cells inside. Each cell in the table represents a coffee+bagel combo. This idea is applied to the section above, but we have a lot more options.
Answer: ![\dfrac{5}{9}](https://tex.z-dn.net/?f=%5Cdfrac%7B5%7D%7B9%7D)
Step-by-step explanation:
When we throw a die , Total outcomes =6
When we throw 3 dice , Total outcomes = 6 x 6 x 6 = 216 [by fundamental counting principle]
Given : Three fair dice are rolled, one red, one green and one blue.
Favorable outcomes : When the upturned faces of the three dice are all of different numbers i.e. no repetition of numbers allowed
By Permutations , the number of favorable outcomes = ![^6P_3=\dfrac{6!}{(6-3)!}=\dfrac{6!}{3!}=6\times5\times4=120](https://tex.z-dn.net/?f=%5E6P_3%3D%5Cdfrac%7B6%21%7D%7B%286-3%29%21%7D%3D%5Cdfrac%7B6%21%7D%7B3%21%7D%3D6%5Ctimes5%5Ctimes4%3D120)
The probability that the upturned faces of the three dice are all of different numbers = ![\dfrac{\text{Favorable outcomes}}{\text{Total outcomes}}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Ctext%7BFavorable%20outcomes%7D%7D%7B%5Ctext%7BTotal%20outcomes%7D%7D)
![=\dfrac{120}{216}=\dfrac{5}{9}](https://tex.z-dn.net/?f=%3D%5Cdfrac%7B120%7D%7B216%7D%3D%5Cdfrac%7B5%7D%7B9%7D)
The probability that the upturned faces of the three dice are all of different numbers is
.
Such a ray that divides an angle into two equal angles is called an angle bisector.
Likewise, two rays that divide an angle into three congruent angles are called angle trisectors. Figure %:
An angle bisected and trisected On the left, angle ABC is bisected by the ray BD.
Credits to google.
In short, no.
Answer:
62.5
Step-by-step explanation:
2cm = 25mi
1cm = 12.5 (25/2)
5cm is 2 + 2 + 1
2 + 2 + 1 = 25 + 25 + 12.5 = 62.5