We know that
[area of a regular hexagon]=6*[area of one <span>equilateral triangle]
</span>210.44=6*[area of one equilateral triangle]
[area of one equilateral triangle]=210.44/6-----> 35.07 cm²
[area of one equilateral triangle]=b*h/2
h=7.794 cm
b=2*area/h------> b=2*35.07/7.794------>b= 9 cm
the length side of a regular hexagon is 9 cm
<span>applying the Pythagorean theorem
</span>r²=h²+(b/2)²------>r²=7.794²+(4.5)²------> r²=81--------> r=9 cm
<span>this last step was not necessary because the radius is equal to the hexagon side------> (remember the equilateral triangles)
</span>
the answer is
the radius is 9 cm
Answer:
Step-by-step explanation:
7) Area = 615.75 sq. km
πr² = 615.75
3.14*r² = 615.75
r² = 615.75/3.14 = 196
r = √196
r = 14 km
8) circumference = 15.71 yards
πd = 15.71
3.14*d = 15.71
d = 15.71/3.14 = 5 yards
9)Area = 415.48 sq.inches
πr² = 415.48
3.14*r² = 415.48
r² = 415.48/3.14 = 132.31
r = √132.31
r = 11.5 inches
diameter = 11.5*2 = 23 inches
Hopes this helps:
Answer: x = -10/7
1. Simplify 2 • 2 to 4
4 + 7x + 6 = 0
2. Simplify 4 + 7x + 6 to 7x + 10.
7x + 10 = 0
3. Subtract 10 from both sides.
7x = -10
4. Divide both sides by 7.
X = -10/7
Answer:
37.35 in
Step-by-step explanation:
The volume of a cone is given by the formula ...
V = (π/3)r²h
where r is the radius of the base and h is the height. We want to find the diameter of the base, so we can rewrite this in terms of diameter and solve for d. Please note that the height is given in millimeters, not inches, so a conversion is necessary.
V = (π/3)(d/2)²h
12V/(πh) = d²
d = 2√(3V/(πh)) = 2√(3(2.2×10^4 in^3)/(π·1530 mm/(25.4 mm/in))
= 2√(1.6764×10^6/(π·1.53×10^3) in^2)
d ≈ 37.35 in
The base diameter of the cone is about 37.35 inches.
