Ask question

Ask question

All categories

2 years ago

9

A sequence of numbers can be thought of as a function, where fin) represents the n term of the sequence. Which of the following

could be the domain of this function?
positive real numbers
O positive integers
Inational numbers
Orational numbers

1 answer:

gladu [14]2 years ago

8 0

Answer:

Rational numbers

Step-by-step explanation I put D on a test and I got it right

You might be interested in

Corinne is paid weekly $356.78. What is her yearly salary?

sveticcg [70]

There are 52 weeks in a year so multiply 356.78 by 52 and you get a yearly salary of 18,552.56 (she probably didnt went to college)

6 0

2 years ago

Read 2 more answers

Prove that the triangle EDF is isosceles. Give reasons for your answer.

Gekata [30.6K]

Answer:

$\triangle EDF$ is isosceles.

Step-by-step explanation:

Please have a look at the attached figure.

We are <u>given</u> the following things:

$\angle EDF = y$

$\text{External }\angle DFG = 90 +\dfrac{y}{2}$

Let us try to find out $\angle E$ and $\angle DFE$ . After that we will compare them.

<u>Finding </u> $\angle DFE$ <u>:</u>

Side EG is a straight line so $\angle GFE = 180$

$\angle GFE$ is sum of internal $\angle DFE$ and external $\angle DFG$

$\angle GFE = 180 = \angle DFE + \angle DFG\\\Rightarrow 180 = \angle DFE + (90+\dfrac{y}{2})\\\Rightarrow \angle DFE = 180 - 90 - \dfrac{y}{2}\\\Rightarrow \angle DFE = 90 - \dfrac{y}{2} ....... (1)$

<u>Finding </u> $\angle E$ <u>:</u>

<u>Property of external angle:</u> External angle in a triangle is equal to the sum of two opposite internal angles of a triangle.

i.e. external $\angle DFG$ = $\angle E + \angle EDF$

$\Rightarrow 90+\dfrac{y}{2} = \angle E + y\\\Rightarrow \angle E = 90+\dfrac{y}{2} -y\\\Rightarrow \angle E = 90-\dfrac{y}{2} ....... (2)$

Comparing equations (1) and (2):

It can be clearly seen that:

$\angle DFE = \angle E =90-\dfrac{y}{2}$

The two angles of $\triangle EDF$ are equal hence $\triangle EDF$ is isosceles.

8 0

2 years ago

Polygon ABCDEF is the result of a translation of polygon GHIJKL . GL¯¯¯¯¯ is parallel to HI¯¯¯¯¯ in the pre-image. please help

marishachu [46]

Since GL and HI are parallel to each other, then in the translation this condition is going to be kept. So that, we can write in these gaps that AB and FE are parallel to each other.

8 0

3 years ago

Can someone please help me with this question?

sattari [20]

The answer would be y=1/7x-4

7 0

2 years ago

5/9 (f – 32) when f = 50

kondor19780726 [428]

10

Hope it’s right best luck with your studying

7 0

2 years ago

Read 2 more answers