The maximum number of turning points in a cubic function is 2.

In this case,

$f(x)=3x^3-x^2+4x-2\implies f'(x)=9x^2-2x+4$

The discriminant is $(-2)^2-4(9)(4)=-140$ , which means the derivative has no real roots. This means there are no critical points and thus no turning points/relative extrema.

5 0

3 years ago

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Can someone explain to me how to do this exercise?

kolbaska11 [484]

Hi
You should put into them.I mean
1-This is 2 part.First, you should put f(-1) then you should put what you found.
Solve is:f(-1)=3(-1)-2(-1)^2 so -3-2=-5 then put in other one:if f(-5):-15-50=-65
Is it correct?

4 0

3 years ago