The mean is 10,
The median is 10,
And there is no mode.
The mean of a set of numbers is the sum divided by the number of terms,
7+15+12+6+10=50
There are 5 numbers in the set,
50/5=10.
10 is the mean.
Arrange the data in an ascending order and the median is the middle value. If the number of values is an even number, the median will be the average of the two middle numbers,
6, 7, 10, 12, 15,
10 is in the middle so it is the median.
The mode is the element that occurs most in the data set. In this case, all elements occur only once, so there is no mode.
Just so you don’t confuse the data with the group sets,
The actual data set is 7, 15, 12, 6, and 10
This data paired with score column or group set means that,
10 people got a score of 1-10
6 people got a score of 11-20
12 people got a score of 21-30
15 people got a score of 31-40
And 7 people got a score of 41-50 :)
The answer is the C let me know if you need the work
Answer:
Low Q1 Median Q3 High
6 9 11 12.5 14
The interquartile range = 3.5
Step-by-step explanation:
Given that:
Consider the following ordered data. 6 9 9 10 11 11 12 13 14
From the above dataset, the highest value = 14 and the lowest value = 6
The median is the middle number = 11
For Q1, i.e the median of the lower half
we have the ordered data = 6, 9, 9, 10
here , we have to values as the middle number , n order to determine the median, the mean will be the mean average of the two middle numbers.
i.e
median = 
median = 
median = 9
Q3, i.e median of the upper half
we have the ordered data = 11 12 13 14
The same use case is applicable here.
Median = 
Median = 
Median = 12.5
Low Q1 Median Q3 High
6 9 11 12.5 14
The interquartile range = Q3 - Q1
The interquartile range = 12.5 - 9
The interquartile range = 3.5
Okay so instead of dividing you will cross multiply.
4n(15)=84(5)
60n=420
420/60=7
Answer: n=7
