Please please please help this is really important, please add work/explanations

Mathematics

1 answer:

Sunny_sXe [5.5K]3 years ago

7 0

Answer:

125

Step-by-step explanation:

hope it help you in some way

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Samples of rejuvenated mitochondria are mutated (defective) in 3% of cases. Suppose 17 samples are studied, and they can be cons

andrey2020 [161]

Answer:

a) 59.58%

b) 90.90%

c) 0%

Step-by-step explanation:

Let p be the probability a sample is mutated. Then q= 1-p is the probability the sample IS NOT mutated.

So p=0.03 (3%) and q=0.97 (97%).

The experiment of finding a mutated sample out of 17 clearly has a binomial distribution, where the probability of finding k mutated samples out of 17 is given by

$P(17;k)=\binom{17}{k}(0.03)^k(0.97)^{17-k}$

We want P(17;0)

$P(17;0)=\binom{17}{0}(0.03)^0(0.97)^{17}=(0.97)^{17}=0.5958=59.58\%$

We want P(17;0)+P(17;1)

$P(17;0)+P(17;1)=0.5958+\binom{17}{1}(0.03)(0.97)^{18}=0.5958+0.3132=0.9090=90.90\%$

We want P(17;9)+P(17;10)+...+P(17;17)

Computing this number, we get

$3.8448*10^{-34}$

This figure is zero if we round to 2 decimals

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3 years ago

What is the formula for P^c(n,r)

lisov135 [29]

P(n,r)= n! /(n-r)!
C(n,r)= n! / r! (n-r)! 
P^c(n,r)= P raised to power C(n.r)? (If so, you know C(n,r) ; raise P to power C(n,r)) 
P(A/B) = P(A ∩ B) / P(B)
Hope this helped :)

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3 years ago

Pls help 6,2 X= 34 6 18

ValentinkaMS [17]

Answer:

c. 16

Step-by-step explanation:

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Answer: