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murzikaleks [220]
3 years ago
9

If a woman takes an early pregnancy test, she will either test positive, meaning that the test says she is pregnant, or test neg

ative, meaning that the test says she is not pregnant. Suppose that if a woman really is pregnant, there is a 98% chance that she will test positive. Also, suppose that if a woman really is not pregnant, there is a 99% chance that she will test negative. Assume that 1000 women are to be pregnancy tested and that exactly 100 of them are pregnant. If a randomly chosen woman from this group tests positive for pregnancy, then what is the probability that she really is pregnant?
Mathematics
1 answer:
k0ka [10]3 years ago
3 0

Answer:

0.0098

Step-by-step explanation:

Probability of being pregnant:100/1000

=1/10.

98% chance:=98/100 ×1/10

=98/1000

Therefore the probability that she really is pregnant is: 0.098

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When you subtract, you are really adding the opposite, so I use theKeep-Change-Change rule.

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The great thing about multiplying and dividing integers is that there is two rules and they apply to both multiplication and division!

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The accurate definition is that the circle that's closest to the 2 dimensional figure where all the set of point in the plane should be equal distance. A example is a point or line.

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