The expected count of visits is the mean or average visits to each feeder
The expected count of visits to the third feeder is 87.5
<h3>How to determine the expected count of visit?</h3>
The table of values is given as:
Feeder 1 2 3 4
Observed visits 80 90 92 88
In this case, the null hypothesis implies that the visits to each feeder are uniformly distributed
So, the expected count is calculated using:
Expected count =Visits/Feeders
This gives
Expected count = 350/4
Evaluate the quotient
Expected count = 87.50
Hence, the expected count of visits to the third feeder is 87.5
Read more about chi square goodness of fit test at:
brainly.com/question/4543358
Is there any choices for it
Step-by-step explanation:
(5.6) × 1/8

Here the unit fraction is 1/8
multiply 5.6 times 1
so its 5.6. then divide the decimal by 8
we know that 8 times 7 is 56
so 56 divide by 8 is 7
we have decimal point 1 number to the left
so we move decimal point 2 place left
Hence 5.6 divide by 8 is 0.7

Answer: 0.7
One way is to just expand it by using binomial theorem
or to use pascal's triangle
ok so
to find the nth term of a binomial, (a-b). where the binomial is to the r power you do
n-1=k
rCk times

and rCk=

so
4th term
4-1=3
6 is exponent
6C3

=

=

=

the 4th term is
4 1/5 + b = 9 3/5
4 1/5 - 4 1/5 + b = 9 3/5 - 4 1/5
(taking the same amount from each side to keep it balanced)
0 + b = 5 2/5
(subtracting 4 1/5 from each side)
b = 5 2/5