What is an equation of the line that passes through the point (8,-4) and is parallel to the line x-4y=12?

1 answer:

7 0

Answer:

x - 4y =12 / -x

-4y = 12 - x // -4

y = -3 1/4 *x

a = 1/4

f(8) = -4

-4 = a*8 + b

-4 = 2 + b / -2

b = -6

y = 1/4 *a -6

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