Question

f r(x) = 3x – 1 and s(x) = 2x + 1, which expression is equivalent to (StartFraction r Over s EndFraction) (6)?

Answer 1

The equivalent expression to $\mathbf{(\dfrac{r}{s})(6)= \dfrac{17}{13}}$

What are the equivalent expressions?

Equivalent expressions are similar expressions that may have different forms but when a value is replaced with the variables in the same form provides the same answer.

From the information given, If:

• r(x) = 3x - 1
• s(x) = 2x + 1

Then the fractional form can be an expression as:

$\mathbf{(\dfrac{r}{s})(x)= \dfrac{3x-1}{2x+1}}$

where;

• x = 6

$\mathbf{(\dfrac{r}{s})(6)= \dfrac{3(6)-1}{2(6)+1}}$

$\mathbf{(\dfrac{r}{s})(6)= \dfrac{18-1}{12+1}}$

$\mathbf{(\dfrac{r}{s})(6)= \dfrac{17}{13}}$

Learn more about equivalent expressions here:

brainly.com/question/24734894

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