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3 years ago

Rewrite the expression 13d - (-9d - 4) without parentheses

Mathematics

2 answers:

dimaraw [331]3 years ago

4 0

13d-(-9d-4)
Transfer minus sign to all numbers in parenthesis. = 13d +9d +4 =

Answer: 22d+4

Arturiano [62]3 years ago

3 0

Answer:

13d- -9d-4

Step-by-step explanation:

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What are the factors of 36?

denis23 [38]

Answer:

1, 2, 3, 4, 6, 9, 12, 18, 36

Step-by-step explanation:

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2 years ago

Freyda has a circular rug with a radius of 120 centimeters. The fringe on the outside edge of the rug needs to be replaced. What

Gnom [1K]

Answer:

The Fringe of the rug is 754 cm.

Step-by-step explanation:

Given:

radius = 120 cm

We need to find the fringe of the outside rug.

Solution:

Since the rug is in the circular form.

We can say that fringe of the outside edge of the rug can be equal to circumference of the circle.

Then we will find the Circumference of the circle.

Circumference of the circle is given 2 times 'π' times radius 'r'.

framing in equation form we get;

Circumference of the circle = $2\pi r$

Circumference of the circle = $2 \times \pi \times 120 = 753.98 \approx 754\ cm$

Hence the Fringe of the rug is 754 cm.

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3 years ago

Experts/ace helpppp plzzz

Dennis_Churaev [7]

point slope form is y=mx+ b

m is slope which is given as 1/2

replace x & y into the equation to solve for b

b = 6

so equation is y =1/2x+6

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4 years ago

Mr. Jones used a fair spinner divided into 4 sections as shown below. They spun the spinner 50 times and recorded the results in

tatuchka [14]

Answer:

The theoretical probability would be 25% or 1/4 because there are four sections but in the example the probability of a one being spun was 24%

Step-by-step explanation:

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3 years ago

Verify that the given point is on the curve and find the lines that are (a) tangent and (b) normal to the curve at the given poi

lara [203]

For each curve, plug in the given point $(x,y)$ and check if the equality holds. For example:

(I) (2, 3) does lie on $x^2+xy-y^2=1$ since 2^2 + 2*3 - 3^2 = 4 + 6 - 9 = 1.

For part (a), compute the derivative $\frac{\mathrm dy}{\mathrm dx}$ , and evaluate it for the given point $(x,y)$ . This is the slope of the tangent line at the point. For example:

(I) The derivative is

$x^2+xy-y^2=1\overset{\frac{\mathrm d}{\mathrm dx}}{\implies}2x+x\dfrac{\mathrm dy}{\mathrm dx}+y-2y\dfrac{\mathrm dy}{\mathrm dx}=0\implies\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{2x+y}{2y-x}$

so the slope of the tangent at (2, 3) is

$\dfrac{\mathrm dy}{\mathrm dx}(2,3)=\dfrac74$

and its equation is then

$y-3=\dfrac74(x-2)\implies y=\dfrac74x-\dfrac12$

For part (b), recall that normal lines are perpendicular to tangent lines, so their slopes are negative reciprocals of the slopes of the tangents, $-\frac1{\frac{\mathrm dy}{\mathrm dx}}$ . For example:

(I) The tangent has slope 7/4, so the normal has slope -4/7. Then the normal line has equation

$y-3=-\dfrac47(x-2)\implies y=-\dfrac47x+\dfrac{29}7$

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3 years ago