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3 years ago

Answer two questions about Systems A and B:

Mathematics

2 answers:

mars1129 [50]3 years ago

6 0

Answer:

1. replace only the left-hand side of one equation with the sum/difference of both equations

2.No

Step-by-step explanation:

Misha Larkins [42]3 years ago

3 0

Answer:

1) replace only the left-hand side of one equation with the sum/difference of both equations

2) no

Step-by-step explanation:

i just did this problem lol

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Rodney created a graph of each given linear equation below, but Rodney made mistakes on each of his graphs. Explain Rodney’s err

iogann1982 [59]

Rodney's errors on each of the graphs given can be explained as in the explanation below.

<h3>Linear graphs of slope-intercept form equations</h3>

Rodney's error on each of the given linear graphs are as follows;

For y= 30x +10;

The slope of the graph is 30 and it's intercept is; 10. Hence, the graph should intersect/touch the y-axis at (0,10)

For y= (-1/2)x +5;

The slope of the given function is; -1/2 and hence, the graph should be a decreasing linear graph.

For y= x -2;

The slope and intercept of the given function are 1 and -2 respectively. On this note, the graphed line should intersect the y-axis at point (0, -2) and the graph should be an increasing linear graph.

Read more on linear graphs;

brainly.com/question/14323743

4 0

3 years ago

A square root function has both x and y intercepts.

Nata [24]

Step-by-step explanation:

Square Root:

The equation will never touch the x - axis or the y - axis,so the function does not have an x - or y- intercept. ...Therefore,the x- and y- intercepts are 0.

I hope it's helpful!

8 0

3 years ago

Find the directional derivative of the function at the given point in the direction of the vector v. f(x, y, z) = xe^y + ye^z +

LUCKY_DIMON [66]

Answer:

$D_{\vec{u}}f(0,0,0)=\frac{6}{\sqrt{54}}$

Step-by-step explanation:

We need to find the directional derivative of the function at the given point in the direction of the vector v.

$f(x, y, z)=xe^{y} + ye^{z} + ze^{x}$ ,point (0, 0, 0) and $v=$

By Theorem: If f is a differentiable function of x , y and z , then f has a directional derivative for any unit vector $\overrightarrow{v} =$ and

$D_{\overrightarrow{u}}f(x,y,z)=f_{x}(x,y,z)u_1+f_{y}(x,y,z)u_2+f_{z}(x,y,z)u_3$

where $\overrightarrow{u}=\frac{\overrightarrow{v}}{||v||}$

since, $v=$

then $\overrightarrow{u}=\frac{\overrightarrow{v}}{||v||}$

$\overrightarrow{u}=< \frac{6}{\sqrt{6^{2}+3^{2}+(-3)^{2}}},\frac{3}{\sqrt{6^{2}+3^{2}+(-3)^{2}}},\frac{-3}{\sqrt{6^{2}+3^{2}+(-3)^{2}}} >$

$\overrightarrow{u}=< \frac{6}{\sqrt{54}},\frac{3}{\sqrt{54}},\frac{-3}{\sqrt{54}} >$

The partial derivatives are

$f_{x}(x,y,z)=e^{y}+ze^{x}$

$f_{y}(x,y,z)=xe^{y}+e^{z}$

$f_{z}(x,y,z)=ye^{z}+e^{x}$

Then the directional derivative is

$D_{\vec{u}}f(x,y,z)=(e^{y}+ze^{x})(\frac{6}{\sqrt{54}})+(xe^{y}+e^{z})(\frac{3}{\sqrt{54}})+(ye^{z}+e^{x})(\frac{-3}{\sqrt{54}})$

so, directional derivative at point (0,0,0)

$D_{\vec{u}}f(0,0,0)=(e^{0}+0e^{0})(\frac{6}{\sqrt{54}})+(0e^{0}+e^{0})(\frac{3}{\sqrt{54}})+(0e^{0}+e^{0})(\frac{-3}{\sqrt{54}})$

$D_{\vec{u}}f(0,0,0)=\frac{6}{\sqrt{54}}+\frac{3}{\sqrt{54}}+\frac{-3}{\sqrt{54}}$

$D_{\vec{u}}f(0,0,0)=\frac{6+3-3}{\sqrt{54}}$

$D_{\vec{u}}f(0,0,0)=\frac{6}{\sqrt{54}}$

3 0

4 years ago

The Anchor Club is conducting a survey to find out if the students in the club want to participate in a school fundraiser. Cindy

Crank

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3 years ago

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A chef cooked 8 kilograms of mashed potatoes for a dinner party if the guests only ate 6/8 of the amount he cooked,how much did

IgorLugansk [536]

Food they ate = Total cooked food x part of food they ate

= 8x 6/8

= 6.

So they ate 6 Kgs of food.

3 0

4 years ago