Answer:
As you had problem in the last answer so I think this is the actual question and the solution according to it.
3÷x-1-3÷x+1=4 solve this equation in in quadratic equation
2 answers:
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Answer:
Step-by-step explanation:
Let's assume this is a straight line, so we can use the basic form of a straight line equation: y=mx+b, where m is the slope and b is the y-intercept (the value of y when x is zero).
The slope is the rate of change of the line, and can be calculated by dividing the change in y by the change in x between any two points. Here: (0,4) and (1,2)
The change in y is known as the "Rise." Going from (0,4) to (1,2), we have a change of -2:
(2 - 4) = -2 This is the Rise (Final minus the initial values)
X changes by 1 (1-0) = 1 (Final minus the initial values)
Rise/Run = -2/1 or -2
The slope, m, is -2. Values of y decrease as x increases.
The equation becomes y = -2x+b
The value of b must be such it forces the line to go between the two points. We can calculate b by i=using one of the two points in out unfinished equation and solve for b. I'll pick (1,2).
y = -2x+b
2 = -2*(1) + b
b = 4
The equation becomes y=-2x+4
