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3 years ago

Please help Can someone answer and tell me how to do this (Will mark brainliest)

Mathematics

1 answer:

Gre4nikov [31]3 years ago

8 0

Answer:

57 degrees

Step-by-step explanation:

Total measurement of any triangle is 180 degrees.

/_V=180-53.8-69.2=57 degrees

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Find the missing angle

inna [77]

THEOREM:

Angle sum property —: The sum of interior angles of a triangle is 180°.

ANSWER:

Let the missing angle be x.

By angle sum property,

∠x + 20° + 80° = 180°
∠x + 100 = 180°
∠x = 180° – 100°
∠x = 80°

So, Correct choice - [C] 80°.

7 0

3 years ago

Read 2 more answers

Round Ed to the nearthest tenth and answer now question

Vikki [24]

Answer:

$y = 9.1$

Step-by-step explanation:

y can be found using the Law of sines as explained below:

m < Y = 106°

m < X = 58°

WY = x = 8

WX = y = ?

Thus,

$\frac{x}{sin(X)} = \frac{y}{sin(Y)}$

$\frac{8}{sin(58)} = \frac{y}{sin(106)}$

$\frac{8}{0.848} = \frac{y}{0.961}$

Multiply both sides by 0.961 to solve for y

$\frac{8}{0.848}*0.961 = \frac{y}{0.961}*0.961$

$\frac{8*0.961}{0.848} = y$

$\frac{8*0.961}{0.848}*0.961 = y$

$9.07 = y$

$y = 9.1$ (to the nearest tenth)

7 0

3 years ago

What is the perimeter of this quadrilateral? (5,5) (2, 4) (4, 1) (6, 1)

lbvjy [14]

$~\hfill \stackrel{\textit{\large distance between 2 points}}{d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}}~\hfill~ \\\\[-0.35em] ~\dotfill\\\\ A(\stackrel{x_1}{5}~,~\stackrel{y_1}{5})\qquad B(\stackrel{x_2}{2}~,~\stackrel{y_2}{4}) ~\hfill AB=\sqrt{[ 2- 5]^2 + [ 4- 5]^2} \\\\\\ AB=\sqrt{(-3)^2+(-1)^2}\implies \boxed{AB=\sqrt{10}} \\\\[-0.35em] ~\dotfill\\\\ B(\stackrel{x_1}{2}~,~\stackrel{y_1}{4})\qquad C(\stackrel{x_2}{4}~,~\stackrel{y_2}{1}) ~\hfill BC=\sqrt{[ 4- 2]^2 + [ 1- 4]^2}$

$BC=\sqrt{2^2+(-3)^2}\implies \boxed{BC=\sqrt{13}} \\\\[-0.35em] ~\dotfill\\\\ C(\stackrel{x_1}{4}~,~\stackrel{y_1}{1})\qquad D(\stackrel{x_2}{6}~,~\stackrel{y_2}{1}) ~\hfill CD=\sqrt{[ 6- 4]^2 + [ 1- 1]^2} \\\\\\ CD=\sqrt{2^2+0^2}\implies \boxed{CD=2} \\\\[-0.35em] ~\dotfill\\\\ D(\stackrel{x_1}{6}~,~\stackrel{y_1}{1})\qquad A(\stackrel{x_2}{5}~,~\stackrel{y_2}{5}) ~\hfill DA=\sqrt{[ 5- 6]^2 + [ 5- 1]^2}$

$DA=\sqrt{(-1)^2+4^2}\implies \boxed{DA=\sqrt{17}} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{\Large Perimeter}}{\sqrt{10}~~ + ~~\sqrt{13}~~ + ~~2~~ + ~~\sqrt{17}}~~ \approx ~~ 12.89$