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Ainat [17]
3 years ago
9

Ineeeddddddyoooouuuurrrrr hhhheeeellllpppp ppppllllssss

Mathematics
2 answers:
SpyIntel [72]3 years ago
5 0

Answer:

d. you just have to multiply everything

ivanzaharov [21]3 years ago
4 0
D. 36cm^3

Hope this helps!
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4x + y< 2
bulgar [2K]

The two inequalities can be rewritten as

\begin{cases}y-2\end{cases}

The solution is composed by every point below the graph of the line y=-4x+2, and above the horizontal line y=-2

To draw the line y=-4x+2 we can build a little table (only 2 points are required):

\begin{array}{c|c}x&y\\0&2\\1&-2\end{array}

So, if you draw the points (0,2) and (1, -2) and connect them, you'll have your line.

To draw the line y=-2, simply pick any point with y coordinate -2, for example (0, -2), and draw a horizontal line.

Choose the above/below areas as specified above to solve the system.

5 0
3 years ago
On what interval is the function h(f)=|x+2|-2 increasing ?
VLD [36.1K]

Answer:

The increasing interval is S=(-2,\infty)

Step-by-step explanation:

This absolute function has a vertex in x=-2. Now, from this point, the function has a positive slope (increasing), which means for values of x equals to -1,0,1,2,3,...,n.

Therefore the interval will

S=(-2,\infty)

I hope it helps you!

7 0
3 years ago
Which of the following represents a geometric sequence? I 1/4, 1/4, 1/4, 1/4 II 1/4, 1/5, 1/6 III 1/4, 1, -4, 1/6 IV 1/4, -4, 1/
LenaWriter [7]
I'm pretty sure it would be none of these because1/4*5=1 and 1/4 then it would be 6 and 1/4 then it would be 31 and 1/4
7 0
3 years ago
Read 2 more answers
find the volume of the following figure round your answer to the nearest tenth if necessary and make sure to use pi
Vikki [24]

Answer:

524cm^2

Step-by-step explanation:

Formula for Volume of sphere= 4/3 πr^2

We have,

r=5cm

Now,

Volume(v)=4/3 πr^2 = 4/3π 5^3= 4/3π 125 = 166.666666667π = 523.598775599

Rounding to the nearest tenth,

Volume=524cm^2

4 0
3 years ago
Absolute value inequality
Marizza181 [45]

|x| because just Google it if I'm wrong

8 0
3 years ago
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