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3 years ago

A team won 8 games and lost 5 games. What’s the Fraction of the games lost?

Mathematics

2 answers:

elena-s [515]3 years ago

6 0

5/8 lost 3/8 won is your correct answer btw I would appreciate Brainly answer

iVinArrow [24]3 years ago

4 0

Answer:

5/8 or 0.625 for wins

3/8 for lost

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HELP!!! Drag the numbers to order them from least to greatest. HELP!!!!

Masteriza [31]

Answer:

-2.86 , -0.37 , 0.19 , 0.91 , 1.46

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

roshaun and lea go to an amusement park. lea spends 1/2 of her money, and roshaun spends 1/4 of his money. is it possible for ro

Olin [163]

Yes it is possible for Roshaun to spend more money than Lea because he could have had more money than her to start with making his fraction larger than hers.

3 0

4 years ago

Consider the trapezoid below.

Nuetrik [128]

Answer:

57cm²

Step-by-step explanation:

area for trapezoid=

b¹+b²=x

x÷2=v

v×h=z

h=height

b=base

14+5=19

19÷2=9.5

9.5×6=57

3 0

3 years ago

1.consider the function

marin [14]

Function transformation involves changing the form of a function

The transformation from f(x) to g(x) is a horizontal shift 3 units left, followed by a vertical stretch by a factor of 4
The x and y intercepts are -0.67 and 1.91, respectively.
The behavior of g(x) is that, g(x) approaches infinity, as x approaches infinity.

The functions are given as:

$\mathbf{f(x) = log3x}$

$\mathbf{g(x) = 4log3(x+1)}$

(a) The transformation from f(x) to g(x)

First, f(x) is shifted left by 1 unit.

The rule of this transformation is:

$\mathbf{(x,y) \to (x + 1,y)}$

So, we have:

$\mathbf{f'(x) = log3(x + 1)}$

Next. f'(x) is vertically stretched by a factor of 4.

The rule of this transformation is:

$\mathbf{(x,y) \to (x,4y)}$

So, we have:

$\mathbf{g(x) = 4log3(x+1)}$

Hence, the transformation from f(x) to g(x) is a horizontal shift 3 units left, followed by a vertical stretch by a factor of 4

(b) Sketch of g(x)

See attachment

(c) Asymptotes

The graphs of g(x) have no asymptote

(d) The intercepts, and the behavior of f(x)

The graph crosses the x-axis at x =-0.67, and it crosses the y-axis at y = 1.91

Hence, the x and y intercepts are -0.67 and 1.91, respectively.

The behavior of g(x) is that, g(x) approaches infinity, as x approaches infinity.

We know this because, the value of the function increases as x increases

Read more about function transformations at:

brainly.com/question/13810353

4 0

3 years ago

HELP ASAP

Andrei [34K]

Answer:

$radius = \sqrt{13}$ or $radius = 3.61$

Step-by-step explanation:

Given

Points:

A(-3,2) and B(-2,3)

Required

Determine the radius of the circle

First, we have to determine the center of the circle;

Since the circle has its center on the x axis; the coordinates of the center is;

$Center = (x,0)$

Next is to determine the value of x through the formula of radius;

$radius = \sqrt{(x_1 - x)^2 + (y_1 - y)^2} = \sqrt{(x_2 - x)^2 + (y_2 - y)^2}$

Considering the given points

$A(x_1,y_1) = A(-3,2)$

$B(x_2,y_2) = B(-2,3)$

$Center(x,y) =Center (x,0)$

Substitute values for $x,y,x_1,y_1,x_2,y_2$ in the above formula

We have:

$\sqrt{(-3 - x)^2 + (2 - 0)^2} = \sqrt{(-2 - x)^2 + (3 - 0)^2}$

Evaluate the brackets

$\sqrt{(-(3 + x))^2 + 2^2} = \sqrt{(-(2 + x))^2 + 3 ^2}$

$\sqrt{(-(3 + x))^2 + 4} = \sqrt{(-(2 + x))^2 + 9}$

Eva;uate all squares

$\sqrt{(-(3 + x))(-(3 + x)) + 4} = \sqrt{(-(2 + x))(-(2 + x)) + 9}$

$\sqrt{(3 + x)(3 + x) + 4} = \sqrt{(2 + x)(2 + x) + 9}$

Take square of both sides

$(3 + x)(3 + x) + 4 = (2 + x)(2 + x) + 9$

Evaluate the brackets

$3(3 + x) +x(3 + x) + 4 = 2(2 + x) +x(2 + x) + 9$

$9 + 3x +3x + x^2 + 4 = 4 + 2x +2x + x^2 + 9$

$9 + 6x + x^2 + 4 = 4 + 4x + x^2 + 9$

Collect Like Terms

$6x -4x + x^2 -x^2 = 4 -4 + 9 - 9$

$2x = 0$

Divide both sides by 2

$x = 0$

This implies the the center of the circle is

$Center = (x,0)$

Substitute 0 for x

$Center = (0,0)$

Substitute 0 for x and y in any of the radius formula

$radius = \sqrt{(x_1 - 0)^2 + (y_1 - 0)^2}$

$radius = \sqrt{(x_1)^2 + (y_1)^2}$

Considering that we used x1 and y1;

In this case we have that; $A(x_1,y_1) = A(-3,2)$

Substitute -3 for x1 and 2 for y1

$radius = \sqrt{(-3)^2 + (2)^2}$

$radius = \sqrt{13}$

$radius = 3.61$ ---Approximated

7 0

4 years ago