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sergeinik [125]
3 years ago
7

Solve: 5x^2 + 25x = 0. x = 0, x = 5 x = 0, x = −5 x = −5, x = 0, x = 5 x = 5, x = 25

Mathematics
1 answer:
MArishka [77]3 years ago
7 0
5x^2 + 25x = 0
5x(x + 5) = 0
x = 0, -5

The answer is: x = 0 and x = -5.
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The coordinates of the vertices of a polygon are (-2, 1). (-3, 3), (-1, 5), (2, 4), and (2, 1). What is the perimeter of the pol
kobusy [5.1K]

Answer:

15.2\ units

Step-by-step explanation:

step 1

Plot the vertices of the polygon to better understand the problem

we have

A(-2, 1). B(-3, 3), C(-1, 5), D(2, 4),E(2, 1)

using a graphing tool

The polygon is a pentagon (the number of sides is 5)

see the attached figure

The perimeter is equal to

P=AB+BC+CD+DE+AE

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

step 2

<em>Find the distance AB</em>

A(-2, 1). B(-3, 3)

substitute in the formula

d=\sqrt{(3-1)^{2}+(-3+2)^{2}}

d=\sqrt{(2)^{2}+(-1)^{2}}

d_A_B=\sqrt{5}=2.24\ units

step 3

<em>Find the distance BC</em>

B(-3, 3), C(-1, 5)

substitute in the formula

d=\sqrt{(5-3)^{2}+(-1+3)^{2}}

d=\sqrt{(2)^{2}+(2)^{2}}

d_B_C=\sqrt{8}=2.83\ units

step 4

<em>Find the distance CD</em>

C(-1, 5), D(2, 4)

substitute in the formula

d=\sqrt{(4-5)^{2}+(2+1)^{2}}

d=\sqrt{(-1)^{2}+(3)^{2}}

d_C_D=\sqrt{10}=3.16\ units

step 5

<em>Find the distance DE</em>

D(2, 4),E(2, 1)

substitute in the formula

d=\sqrt{(1-4)^{2}+(2-2)^{2}}

d=\sqrt{(-3)^{2}+(0)^{2}}

d_D_E=\sqrt{9}\ units

d_D_E=3\ units

step 6

<em>Find the distance AE</em>

A(-2, 1).E(2, 1)

substitute in the formula

d=\sqrt{(1-1)^{2}+(2+2)^{2}}

d=\sqrt{(0)^{2}+(4)^{2}}

d_A_E=\sqrt{16}\ units

d_A_E=4\ units

step 7

Find the perimeter

P=AB+BC+CD+DE+AE

substitute the values

P=2.24+2.83+3.16+3+4=15.23\ units

Round to the nearest tenth of a unit

P=15.2\ units

6 0
3 years ago
The sum of 1 and 7 times a number is 64. write and solve an equation to determine the number. select the solution and graph that
vichka [17]

x = 8, 1 + 7 +8 and 8 x 8 equals 64. good luck!

3 0
3 years ago
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The line segment shown is rotated 90° clockwise about the origin. What are the new coordinates of point B?
Monica [59]
I’m pretty sure the answers is B
6 0
3 years ago
Triangle DEF (not shown) is similar to ABC shown, with angle B congruent to angle E and angle C congruent to angle F. The length
Bezzdna [24]

Answer:

Area of ΔDEF is 45\ cm^2.

Step-by-step explanation:

Given;

ΔABC and  ΔDEF is similar and ∠B ≅ ∠E.

Length of AB = 2\ cm and

Length of DE = 6\ cm

Area of ΔABC = 5\ cm^2

Solution,

Since, ΔABC and  ΔDEF is similar and ∠B ≅ ∠E.

Therefore,

\frac{Area\ of\ triangle\ 1}{Area\ of\ triangle\ 2} =\frac{AB^2}{DE^2}

Where triangle 1 and triangle 2 is  ΔABC and  ΔDEF respectively.

If two triangles are similar, then the ratio of the area of both triangles is proportional to the square of the ratio of their corresponding sides.

\frac{5}{Area\ of\ triangle\ 2} =\frac{2^2}{6^2}\\ \frac{5}{Area\ of\ triangle\ 2}=\frac{4}{36}\\ Area\ of\ triangle\ 2=\frac{5\times36}{4} =5\times9=45\ cm^2

Thus the area of  ΔDEF is 45\ cm^2.

4 0
3 years ago
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How many solutions does the following equation have, and what are the signs of the solutions? 5x^2 - 9x=2
Bad White [126]
The solutions are:
x = 2 and
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4 0
3 years ago
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