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Mamont248 [21]
3 years ago
5

The box plots shows the length of the songs on 2 diggital music players in minutes which statement best supported by the informa

tion in the box plots
Mathematics
2 answers:
Triss [41]3 years ago
8 0

Answer:

The interquartile range of the data for Music Player X is equal to the interquartile range of the data for Music Player Y.

Step-by-step explanation:

NISA [10]3 years ago
5 0

Answer:

You have to go on a cite called Math and Way buth without the and and no space between math and way

Step-by-step explanation:

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What is 3.2 x 10^-8 expressed as a decimal?
aniked [119]

Answer:

3.2MULTIPLY10-8

Step-by-step explanation:BECUASE THERE IS A NEGATIVE SENSE AND WHEN YOU PRESS YOUR CALACULTAOR U WILL SEE IT TRY IT IF DONT UNDERSTAND LET ME KNOW AGAIN THANKS

4 0
3 years ago
What is the distance between Point A and Point B?
Lelechka [254]

Answer:

"2 units" is the answer.

7 0
3 years ago
Read 2 more answers
Find two postive numbers such that the ratio of the two numbers is 5 to 3 and the product of the two numbers is 540.
svet-max [94.6K]

Answer:

337.5 and also 202.5

Step-by-step explanation:

do 8x = 540 since 5 and 3 are in a ratio... so you get 5x plus 3x. Then you solve for x and get 67.5..67.5 times 3 is 202.5 and 67.5 times 5 is 337.5.

8 0
3 years ago
Read 2 more answers
15. 3x – 4y = -1<br> 5x + 2y = 7
never [62]

Answer:

x = 1, y = 1

Step-by-step explanation:

3x - 4y = -1

5x + 2y = 7

If we multiply the whole second equation by 2, we get:

10x + 4y = 14

Adding this to the first equation:

10x + 4y + 3x - 4y = 14 - 1

13x = 13

x = 1

Applying this to the second equation:

5 (1) + 2y = 7

2y = 2

y = 1

8 0
3 years ago
Solve the following equation by completing the square. 3x^2-3x-5=13
mr Goodwill [35]

we'll start off by grouping some

\bf 3x^2-3x-5=13\implies (3x^2-3x)-5=13\implies 3(x^2-x)-5=13 \\\\\\ 3(x^2-x)=18\implies (x^2-x)=\cfrac{18}{3}\implies (x^2-x)=6\implies (x^2-x+~?^2)=6

so we have a missing guy at the end in order to get the a perfect square trinomial from that group, hmmm, what is it anyway?

well, let's recall that a perfect square trinomial is

\bf \qquad \textit{perfect square trinomial} \\\\ (a\pm b)^2\implies a^2\pm \stackrel{\stackrel{\text{\small 2}\cdot \sqrt{\textit{\small a}^2}\cdot \sqrt{\textit{\small b}^2}}{\downarrow }}{2ab} + b^2

so we know that the middle term in the trinomial, is really 2 times the other two without the exponent, well, in our case, the middle term is just "x", well is really -x, but we'll add the minus later, we only use the positive coefficient and variable, so we'll use "x" to find the last term.

\bf \stackrel{\textit{middle term}}{2(x)(?)}=\stackrel{\textit{middle term}}{x}\implies ?=\cfrac{x}{2x}\implies ?=\cfrac{1}{2}

so, there's our fellow, however, let's recall that all we're doing is borrowing from our very good friend Mr Zero, 0, so if we add (1/2)², we also have to subtract (1/2)²

\bf \left( x^2 -x +\left[ \cfrac{1}{2} \right]^2-\left[ \cfrac{1}{2} \right]^2 \right)=6\implies \left( x^2 -x +\left[ \cfrac{1}{2} \right]^2 \right)-\left[ \cfrac{1}{2} \right]^2=6 \\\\\\ \left(x-\cfrac{1}{2} \right)^2=6+\cfrac{1}{4}\implies \left(x-\cfrac{1}{2} \right)^2=\cfrac{25}{4}\implies x-\cfrac{1}{2}=\sqrt{\cfrac{25}{4}} \\\\\\ x-\cfrac{1}{2}=\cfrac{\sqrt{25}}{\sqrt{4}}\implies x-\cfrac{1}{2}=\cfrac{5}{2}\implies x=\cfrac{5}{2}+\cfrac{1}{2}\implies x=\cfrac{6}{2}\implies \boxed{x=3}

6 0
3 years ago
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