Solve for super big brain
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If for the slower printer it takes 10 hours for the whole thing, how much has it done in 1 hour? well, since it takes 10 hours total, in 1 hour it has only done 1/10 th of the whole work.
the faster printer however, can do it in 6 total, how much has it done in 1 hour? well, 1/6 of the whole work.
now, let's say, they both work together, and it takes "t" hours to finish the whole thing with both rolling.
let's add both rates to see how much that is,
which is 3 hours and 45 minutes.
the faster printer however, can do it in 6 total, how much has it done in 1 hour? well, 1/6 of the whole work.
now, let's say, they both work together, and it takes "t" hours to finish the whole thing with both rolling.
let's add both rates to see how much that is,
which is 3 hours and 45 minutes.
<em>Greetings from Brasil...</em>
For QR: we need to use the Sine Law in Any Triangle....
QS/SEN 72 = QR/SEN 25
6/SEN 72 = QR/SEN 25
6,3 = QR/SEN 25
<h3>QR = 2,66</h3>For PS: we need to use the Cosine Law in Any Triangle....
PS² = PQ² + QS² - 2.PQ.QS.COS Q
PS² = 7,4² + 6² - 2.(7,4).6.COS 34
PS² = 90,76 - 73,61
PS = √17,14
<h3>PS = 4,14</h3>For area we use Heron's Formula 2x.....
for ΔQRS = A1:
A1 = √[P.(P - QR).(P - RS).(P - QS)]
<em>where P = (QR + RS + QS)/2</em>
<em>A1 = </em>√[P.(P - QR).(P - RS).(P - QS)]
<em> </em><em>RS = 6,26 </em><em>(using RS/SEN 97 = QS/SEN 72)</em>
P = (2,66 + 6,26 + 6)/2
P = 14,92/2 ⇒ P = 7,46
A1 = √[7,46.(7,46 - 2,66).(7,46 - 6,26).(7,46 - 6)]
A1 = 7,92
for ΔPQS = A2:
A2 = √[P.(P - PQ).(P - PS).(P - QS)]
P = (7,4 + 4,14 + 6)/2 = 8,77
A2 = √[8,77.(8,77 - 7,4).(8,77 - 4,14).(8,77 - 6)]
A2 = 12,41
Total Area = A1 + A2
Total Area = 7,92 + 12,41
<h3>Total Area = 20,33</h3><em>see more:</em>
