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Katena32 [7]
3 years ago
13

Find the volume of the cone.

Mathematics
1 answer:
lutik1710 [3]3 years ago
8 0

Answer:

B

Step-by-step explanation:

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To find the domain of a function you have to find all the possible input values.
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Answer:

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Step-by-step explanation:

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3 years ago
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A cylinder is placed within a cube. The diameter of the cylinder is equal to the length of each side of the cube. What is the vo
pochemuha

The volume of a shape is the amount of space in it.

<em>The volume outside the cylinder, but inside the cube is 214.6 cubic inches</em>

The given parameter is:

l = 10 ---- length of the cube

So, the volume of the cube is:

V_1 = l^3

V_1 = 10^3

V_1 = 1000

The volume of the cylinder is:

V_2 = \pi r^2h

The diameter (d) of the cylinder equals the length of the cube.

This means that:

d = l

d = 10

Divide by 2 to calculate the radius of the cylinder

r = \frac{10}{2}

r = 5

Also, the height of the cube is::

h =l

h =10

So, we have:

V_2 = \pi r^2h

V_2 = \pi \times 5^2 \times 10

V_2 = \pi \times 25 \times 10

V_2 = \pi \times 250

V_2 = 785.4

So, the volume (V) outside the cylinder is:

V = V_1 - V_2

V = 1000 - 785.4

V = 214.6

Hence, the volume outside the cylinder is 214.6 cubic inches

Read more about volumes at:

brainly.com/question/15861918

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3 years ago
Y=-5x+6<br> y=3x-2<br><br> Find the solution to the system of equations.
Kobotan [32]

Answer:

(1, 1 )

Step-by-step explanation:

Given the 2 equations

y = - 5x + 6 → (1)

y = 3x - 2 → (2)

Since both equations express y in terms of x, equate the right sides

3x - 2 = - 5x + 6 ( add 5x to both sides )

8x - 2 = 6 ( add 2 to both sides )

8x = 8 ( divide both sides by 8 )

x = 1

Substitute x = 1 into either of the 2 equations for corresponding value of y

Substituting x = 1 in (2)

y = 3(1) - 2 = 3 - 2 = 1

Solution is (1, 1 )

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3 years ago
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Pls help me to answer this<br>Own words*​
slava [35]

Answer:

I hope it will help you.

Step-by-step explanation:

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There's few lines for you. I hope you like it

An Awesome Math

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<u>Difficult</u> To Part With,

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