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Katyanochek1 [597]
2 years ago
11

What of the following is true for all parallelograms? (2 points)

Mathematics
1 answer:
NeX [460]2 years ago
5 0

Answer:

a

Step-by-step explanation:

These are basic properties of parallelograms and there's really no way to explain other than memorizing them.

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Can you help me? <br><br> 4+3(x+5)=5x-7
PSYCHO15rus [73]

Answer:

13

Step-by-step explanation:

4 + 3(x + 5)=5 x - 7

3x + 19=5x - 7

3x + 19 - 19=5x - 7 - 19

3x =5x - 26

3x - 5x=5x - 26 - 5x

-2= -26

-2x/-2 = -26/-2

x= 13

It might be wrong. I may have made a mistake with typing sorry.

Hope this helps a bit.

6 0
2 years ago
Write 36 divided by 4 in word expression
tigry1 [53]

Idk if this will help but here. Thirty six divided by four equals nine.

8 0
3 years ago
What transformation to the graph occurs when f(x) = x^2 is changed to f(x) = 3(x-2)^2?
miskamm [114]

Answer:

Step-by-step explanation:

The -2 in the parentheses moves the graph horizontally 2 units to the right.

The 3 then stretches this graph vertically by a factor 3.

7 0
2 years ago
You are rolling two dice at the same time. What is the probability of rolling a sum of 5 or 9?
baherus [9]
You can get a 5 by rolling :
1 and 4
2 and 3
3 and 2
4 and 1

You can get a 9 by rolling :
3 and 6
4 and 5
5 and 4
6 and 3

There are 36 possible outcomes, hence your probability is \frac{4\cdot2}{36}=\boxed{\frac29}
8 0
2 years ago
Read 2 more answers
Which are the solutions of x2 = 19x + 1?
Finger [1]

Answer:

(\frac{19-\sqrt{365}} {2},\frac{19+\sqrt{365}} {2})

Step-by-step explanation:

we have

x^2=19x+1

we know that

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}

in this problem we have

-x^{2}-19x-1=0  

so

a=1\\b=-19\\c=-1

substitute in the formula

x=\frac{-(-19)\pm\sqrt{-19^{2}-4(1)(-1)}} {2(1)}

x=\frac{19\pm\sqrt{365}} {2}

x=\frac{19+\sqrt{365}} {2}

x=\frac{19-\sqrt{365}} {2}

(\frac{19-\sqrt{365}} {2},\frac{19+\sqrt{365}} {2})

therefore

StartFraction 19 minus StartRoot 365 EndRoot Over 2 EndFraction comma StartFraction 19 + StartRoot 365 EndRoot Over 2 EndFraction

6 0
3 years ago
Read 2 more answers
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