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Rzqust [24]
3 years ago
12

Can someone please help me?

Mathematics
1 answer:
uysha [10]3 years ago
8 0

Answer:  

= _51_x+ __1_y

    10          5

Step-by-step explanation:

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A 12 by 15 inch picture is mounted on a wall and surrounded by a border of uniform width.
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5 0
3 years ago
a Members of a soccer team raised $1530.50 to go to a tournament. They rented a bus for $1164.50 and budgeted $30.50 per player
Helen [10]

The number of players that can be taken to the tournament is 12 players.

The equation that can be used to represent the total amount spent by the soccer team is:

Total amount spent = cost of rented bus + (cost per meal x total number of players)

$1530.50 = $1164.50 + $30.50x

Where: x = total number of player

In order to determine the value of x, the following steps would be taken:

Combine similar terms

$1530.50 - $1164.50 = $30.50x

$366 = $30.50x

Divide both sides of the equation by 30.50

x = $366 / $30.50

x = 12 players

A similar question was answered here: brainly.com/question/22358515

3 0
2 years ago
The product of a non zero rational number and a irrational number is always sometimes or never irrational
Kryger [21]
Always. The only way an irrational number can become rational is if it’s multiplied by a irrational number.

Hope this helps!
7 0
3 years ago
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What does Luffy from One Piece like better?
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3 years ago
Read 2 more answers
Circle O, with center (x, y), passes through the points A(0, 0), B(–3, 0), and C(1, 2). Find the coordinates of the center of th
balandron [24]
The answer:

the main formula of the circle's equation is 
(x-a)²+ (y-b)² = R²
where C(a, b) is the center of the circle
R is the radius

if a point A(x', y') passes through the circle, so the equation of the circle can be written as 
(x'-a)²+ (y'-b)² = R², and that is  a main formula.


<span>Circle O, with center (x, y), passes through the points A(0, 0), B(–3, 0), and C(1, 2), so we have exactly three equation:
</span>
(0-x)² + (0-y)² = R², circle O passes through A
x²+y²= R²
(-3 -x)² + (0-y)² = R², circle O passes through B
(-3 -x)² + (y)² = R²
(1-x)² + (2-y)² = R², circle O passes through A
(1-x)² + (2-y)² = R²

and we know that R= OA = OC= OB, 
OA=R= sqrt( (0-x)² + (0-y)² ) = OB = sqrt((-3 -x)² + (0-y)²), this implies

x²+y² = (-3 -x)² + (0-y)² , it implies x² = 9+ x² + 6x , and then -9/6=x, x= -3/2
and when OA = OC
x²+y² =(1-x)² + (2-y)²  so, x²+y² =1+x²-2x +4+y²-4y, therefore -5= -2x -4y
 -5= -2x -4y, when x = -3 /2   we obtain y = 2

the center is C(-3/2, 2)
7 0
3 years ago
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