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3 years ago

Each Figure is a Rhombus. Solve for x.OB = 8x+2BR = 4x+20

1 answer:

7 0

For OB divide 8x by 8 and do the same to the 2 (8x/8 )and you just stay with the x an then you divide 2 and 8 and you get 0.25 and that’s your answer ( x = 0.25)
For BR you divide 4x by 4 and keep the x (4x/4) and then you divide 20 by 4 and get 5 and that’s your answer ( x = 5)

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3 years ago

The circumference of a circle with an area of 1,809.56 square centimeters

Virty [35]

$\bf \textit{area of a circle}\\\\
A=\pi r^2~~
\begin{cases}
r=radius\\
------\\
A=1809.56
\end{cases}\implies 1809.56=\pi r^2
\\\\\\
\cfrac{1809.56}{\pi }=r^2\implies \boxed{\sqrt{\cfrac{1809.56}{\pi }}=r}\\\\
-------------------------------\\\\
\textit{circumference of a circle}\\\\
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3 years ago

A friend has a 83% average before the final exam for a course. That score includes everything but the final, which counts for 25

Klio2033 [76]

Answer:

$\mathrm{Best\:course\:grade\:possible:\:}87.25\%,\\\mathrm{Minimum\:score\:on\:final\:to\:earn\:at\:least\:a\:75\%\:for\:the\:course:\:}51\%$

Step-by-step explanation:

Assuming the maximum score for the final is $100\%$ , we can multiply each score by its respective course weight and add them together to give a final score. If your friend did receive this maximum score of $100\%$ , their overall grade for the course would be:

$83(1-0.25)+100(0.25)=\fbox{$87.25\%$}$ .

To find the minimum score they need to earn a 75% for the course, we set up the following equation:

$83(1-0.25)+x(0.25)=75$ , where $x$ is the minimum score she needs.

Solving, we get:

$62.25+x(0.25)=75,\\x(0.25)=12.75,\\x=\fbox{$51\%$}$ .

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3 years ago

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damaskus [11]

Answer:

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Step-by-step explanation:

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3 years ago

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True [87]

$\bf \begin{array}{llllll}
\textit{something}&&\textit{varies inversely to}&\textit{something else}\\ \quad \\
\textit{something}&=&\cfrac{{{\textit{some value}}}}{}&\cfrac{}{\textit{something else}}\\ \quad \\
y&=&\cfrac{{{\textit{k}}}}{}&\cfrac{}{x}
\\
&&y=\cfrac{{{ k}}}{x}
\end{array}\\\\
-----------------------------\\\\
\textit{now, we know that }
\begin{cases}
y=120\\
x=7
\end{cases}\implies 120=\cfrac{k}{7}$

solve for "k", to find "k" or "constant of variation"

7 0

3 years ago

Each Figure is a Rhombus. Solve for x.OB = 8x+2BR = 4x+20​

Each Figure is a Rhombus. Solve for x.OB = 8x+2BR = 4x+20