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Triss [41]
3 years ago
12

The perimeter of a rectangle is 64 feet. The length of the rectangle is 3 times the width of the rectangle. If w represents the

width of the rectangle, the equation that represents the perimeter is 2(3w)+2w=64 . Which shows the first step that should be taken to verify that the width of the rectangle is 8?
2(8)+2(8)=64
2(3+8)+(2+8) =64
2(3(8))2(8)=64
2(3+8)2(8)=64
Mathematics
2 answers:
Sliva [168]3 years ago
8 0
The third answer would be correct.
In-s [12.5K]3 years ago
6 0

Answer:

2(3(8))+2(8)=64

Step-by-step explanation:

Here, w represents the width of the rectangle,

∵ length of the rectangle is 3 times the width of the rectangle,

So, length = 3w,

Since, the perimeter of a rectangle, P = 2(length + width)

= 2(w + 3w)

= 2w + 2(3w)

If P = 64 feet,

⇒ 2w +2(3w) = 64

⇒ 2w + 6w = 64

⇒ 8w = 64

⇒ w = 8

Verification :

P = 2(8) + 2((3(8)) = 16 + 48 = 64 feet

Hence, the first step that should be taken to verify that the width of the rectangle is 8 is 2(3(8))+2(8)=64

Note : a solution obtain from an equation is verified by substituting the value in the equation.

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Answer:

121 cm²

Step-by-step explanation:

Square's area formula is

A=a²

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A=(11 cm)²

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whenever you're talking of area you put cm²

8 0
2 years ago
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Given:

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Solution:

We have,

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Here, 6 quarts is equal to \dfrac{6}{4} gallon. It means we need to multiply 6 by 4 in 4\text{ quarts}=1\text{ gallon} to find the answer.

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After 25 days. 300=triple 100+8x=300. is that 20 words?
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A glass paperweight has a composite shape: a square pyramid fitting exacty on top of an 8 centimeter cube. The pyramid has a hei
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Answer:

Part 1) The volume of the paperweight is 576\ cm^{3}

Part 2) The total surface area of the paperweight is 400\ cm^{2}

Step-by-step explanation:

Part 1) what is the volume of the paperweight?

we know that

The volume of the paperweight is equal to the volume of the square pyramid plus the volume of the cube

step 1

Find the volume of the pyramid

The volume of the pyramid is equal to

V=\frac{1}{3}BH

where

B is the area of the square base

H is the height of the pyramid

B=8^{2}=64\ cm^{2}

H=3\ cm

substitute

V=\frac{1}{3}(64)(3)=64\ cm^{3}

step 2

Find the volume of the cube

The volume of the cube is equal to

V=b^{3}

V=8^{3}=512\ cm^{3}

step 3

Find the volume of the paperweight

64\ cm^{3}+512\ cm^{3}=576\ cm^{3}

Part 2) what is the total surface area of the paperweight?​

we know that

The total surface area of the paperweight is equal to the surface area of 5 faces of the cube plus the lateral area of the pyramid

step 1

Find the surface area of 5 faces of the cube

SA=5b^{2}

SA=5(8^{2})=320\ cm^{2}

step 2

Find the lateral area of the pyramid

LA=4[\frac{1}{2}bh]

LA=4[\frac{1}{2}(8)(5)]=80\ cm^{2}

step 3

Find the total surface area of the paperweight

320\ cm^{2}+80\ cm^{2}=400\ cm^{2}

8 0
3 years ago
A can is 4 inches wide and 8 inches tall. To the nearest whole number, what is the area of a label that wraps around the can if
Yakvenalex [24]

Answer:

The area of a label is 62.8\ in^{2}

Step-by-step explanation:

we know that

The lateral area of a cylinder (label of the can) is equal to

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we have that

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so

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h=8-3=5\ in ----> height of the label

substitute in the formula

LA=2(3.14)(2)(5)=62.8\ in^{2}

5 0
3 years ago
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