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2 years ago

Please answer quickly its a test and i need to get a good grade on it, will give brainliest

Mathematics

1 answer:

Helga [31]2 years ago

3 0

I think the answer is A because it I'm right it did double the size.

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A deep-sea diver dives from the surface to 131 feet below the

Darina [25.2K]

Answer:

146 feet below the surface

Step-by-step explanation:

$-131+8-18-28+23=-146$

8 0

1 year ago

Convert into percentages 7/25

LekaFEV [45]

Answer:

28%

Step-by-step explanation:

Divide the numerator by the denominator in order to convert this fraction into a decimal.

7/25 = 0.28

Multiply the decimal by 100 to convert into a whole number.

.28 * 100 = 28

7/25 converted into a percent is 28%.

8 0

3 years ago

What’s the answer 4±√10

valina [46]

Answer:

Step-by-step explanation:

1 because it 1 and I know it one I need help 1

3 0

3 years ago

Let P = 0.5 0.1 0.5 0.9 be the transition matrix for a Markov chain with two states. Let x0 = 0.5 0.5 be the initial state vecto

max2010maxim [7]

Answer:

Complete solution is given in the images attached below for better demonstration

7 0

2 years ago

How to solve logarithmic equations as such

Serga [27]

$\bf \textit{exponential form of a logarithm} \\\\ \log_a b=y \implies a^y= b\qquad\qquad a^y= b\implies \log_a b=y \\\\\\ \begin{array}{llll} \textit{Logarithm of exponentials} \\\\ \log_a\left( x^b \right)\implies b\cdot \log_a(x) \end{array} ~\hspace{7em} \begin{array}{llll} \textit{Logarithm Cancellation Rules} \\\\ log_a a^x = x\qquad \qquad \stackrel{\textit{we'll use this one}}{a^{log_a x}=x} \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}$

$\bf \log_2(x-1)=\log_8(x^3-2x^2-2x+5) \\\\\\ \log_2(x-1)=\log_{2^3}(x^3-2x^2-2x+5) \\\\\\ \log_{2^3}(x^3-2x^2-2x+5)=\log_2(x-1) \\\\\\ \stackrel{\textit{writing this in exponential notation}}{(2^3)^{\log_2(x-1)}=x^3-2x^2-2x+5}\implies (2)^{3\log_2(x-1)}=x^3-2x^2-2x+5$

$\bf (2)^{\log_2[(x-1)^3]}=x^3-2x^2-2x+5\implies \stackrel{\textit{using the cancellation rule}}{(x-1)^3=x^3-2x^2-2x+5} \\\\\\ \stackrel{\textit{expanding the left-side}}{x^3-3x^2+3x-1}=x^3-2x^2-2x+5\implies 0=x^2-5x+6 \\\\\\ 0=(x-3)(x-2)\implies x= \begin{cases} 3\\ 2 \end{cases}$

5 0

3 years ago