O1:2:1 because they are carbon, hydrogen and oxygen
A control group is going to be something that you don’t “experiment on or change. It is grown or watched under normal conditions. This way you have a medium to say how things are “supposed” to go.
The experimental group is going to be where you “experiment” and change the normal conditions to see what outcome will occur ( under different conditions then normal )
Answer: The answer is the Stratosphere.
Answer:
In technical term, application of fertilizer(s) to soil before sowing of seeds or planting of seedlings is called basal application. Subsequent application of fertilizers to the crops is called topdressing.
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83.235 grams of CaCl2 is required to make 1 litre of 0.75M solution.
Explanation:
Molarity or molar concentration is the number of moles of solute that can be dissolved in 1 L of a solution.
let us find the number of moles
n=C*V Concentration is 0.75M
Volume is 1000ml.
n= 0.75*1
n= 0.75
This means there are 0.75 moles of CaCl2 in 1000 ml of solution of .75M.
Molar mass of CaCl2 is = 40.08+ 2(35.5)
= 110.98 gms
Thus 1 MOLE OF CaCl2 weighs 110.98
so 0.75 moles will weigh 110.98*0.75
= 83.235 grams of CaCl2 is required to make 1 litre of 0.75M solution.