Answer:
![2\sqrt{34}](https://tex.z-dn.net/?f=2%5Csqrt%7B34%7D)
Step-by-step explanation:
We can add a line to create a triangle and a rectangle. The triangle will have side lengths 10 and 6. Furthermore, it will be a right triangle, meaning we can apply the Pythagorean Theorem to find x, the hypotenuse.
![6^2 + 10^2 = x^2\\x = \sqrt{6^2 + 10^2}\\ = \sqrt{136} \\= 2\sqrt34}](https://tex.z-dn.net/?f=6%5E2%20%2B%2010%5E2%20%3D%20x%5E2%5C%5Cx%20%3D%20%5Csqrt%7B6%5E2%20%2B%2010%5E2%7D%5C%5C%20%3D%20%5Csqrt%7B136%7D%20%5C%5C%3D%202%5Csqrt34%7D)
hope this helped! :)
The quotient is 202/21 simplified 9 13/21
4(2a-6)+8b=4(2*8-6)+8*3. Use PEMDAS. 4(16-6)+24. 4(10)+24=40+24. 40+24=64.
Answer:
Composite
Step-by-step explanation:
You can get 87 by multiplying 29x3 so that means it is composite because you cna multiply it by something other than 87x1