Ask question

Ask question

All categories

2 years ago

13

a spinner has 8 sections 2 purple 2 yellow 3 blue and 1 red what is the probability of spinning and landing on a blue or purple

section

1 answer:

alexdok [17]2 years ago

7 0

Answer:

5/8 is the probability.

Step-by-step explanation:

You might be interested in

Ive been waiting hours for someone to answer this question. Is everyone an idiot.

stepan [7]

Answer:

D) x = -2/3 and x = 6

Step-by-step explanation:

4(x²−x+2)−(x+10)(x+2) Distribute

(4)(x²) + (4)(−x) + (4)(2) + − x² + −12x + −20 Multiply

4x² + −4x + 8 + −x² + −12x + −20 Combine like terms

(4x² + −x²) + (−4x + −12x) + (8 + −20) Combine like terms

3x² −16x −12 = 0

x = -2/3 and x = 6

I graphed the equation on the graph below.

If this answer is correct, please make me Brainliest!

7 0

3 years ago

Mid-West Publishing Company publishes college textbooks. The company operates an 800 telephone number whereby potential adopters

s344n2d4d5 [400]

The various answers to the question are:

To answer 90% of calls instantly, the organization needs four extension lines.
The average number of extension lines that will be busy is Four
For the existing phone system with two extension lines, 34.25 % of calls get a busy signal.

<h3>How many extension lines should be used if the company wants to handle 90% of the calls immediately?</h3>

a)

A number of extension lines needed to accommodate $90 in calls immediately:

Use the calculation for busy k servers.

$P_{j}=\frac{\frac{\left(\frac{\lambda}{\mu}\right)^{j}}{j !}}{\sum_{i=0}^{k} \frac{\left(\frac{\lambda}{\mu}\right)^{t}}{i !}}$

The probability that 2 servers are busy:

The likelihood that 2 servers will be busy may be calculated using the formula below.

$P_{2}=\frac{\frac{\left(\frac{20}{12}\right)^{2}}{2 !}}{\sum_{i=0}^{2} \frac{\left(\frac{20}{12}\right)^{t}}{i !}}$$\approx 0.3425$$

Hence, two lines are insufficient.

The probability that 3 servers are busy:

Assuming 3 lines, the likelihood that 3 servers are busy may be calculated using the formula below.

$P_{j}=\frac{\frac{\left(\frac{\lambda}{\mu}\right)^{j}}{j !}}{\sum_{i=0}^{2} \frac{\left(\frac{\lambda}{\mu}\right)^{i}}{i !}}$ \\\\$P_{3}=\frac{\frac{\left(\frac{20}{12}\right)^{3}}{3 !}}{\sum_{i=0}^{3} \frac{\left(\frac{20}{12}\right)^{1}}{i !}}$$\approx 0.1598$$

Thus, three lines are insufficient.

The probability that 4 servers are busy:

Assuming 4 lines, the likelihood that 4 of 4 servers are busy may be calculated using the formula below.

$P_{j}=\frac{\frac{\left(\frac{\lambda}{\mu}\right)^{j}}{j !}}{\sum_{i=0}^{k} \frac{\left(\frac{\lambda}{\mu}\right)^{t}}{i !}}$ \\\\$P_{4}=\frac{\frac{\left(\frac{20}{12}\right)^{4}}{4 !}}{\sum_{i=0}^{4} \frac{\left(\frac{20}{12}\right)^{7}}{i !}}$$

Generally, the equation for is mathematically given as

To answer 90% of calls instantly, the organization needs four extension lines.

b)

The probability that a call will receive a busy signal if four extensions lines are used is,

$P_{4}=\frac{\left(\frac{20}{12}\right)^{4}}{\sum_{i=0}^{4} \frac{\left(\frac{20}{12}\right)^{1}}{i !}} $\approx 0.0624$$

Therefore, the average number of extension lines that will be busy is Four

c)

In conclusion, the Percentage of busy calls for a phone system with two extensions:

The likelihood that 2 servers will be busy may be calculated using the formula below.

$P_{j}=\frac{\left(\frac{\lambda}{\mu}\right)^{j}}{j !}$$\\\\$P_{2}=\frac{\left(\frac{20}{12}\right)^{2}}{\sum_{i=0}^{2 !} \frac{\left(\frac{20}{12}\right)^{t}}{i !}}$$\approx 0.3425$$

For the existing phone system with two extension lines, 34.25 % of calls get a busy signal.

Read more about signal

brainly.com/question/14699772

#SPJ1

3 0

1 year ago

The temperature after a decrease of 5°F from a temperature of −5°F.will have a result of zero?

ycow [4]

No it will be -10 degrees

4 0

3 years ago

The annount of time (in minutes) that it takes to put out a fire varies inversely

sveticcg [70]

Given that the amount of time varies inversely with G.

It can be written as,

$T G=K$

where K is the constant.

We need to determine the time it takes to put out the fire when 200 gallons of water are used.

<u>The value of constant:</u>

When $G=8, T=12$ , we get;

$(12)(8)=K$

$96=K$

Thus, the value of constant is 96.

<u>Time taken:</u>

Substituting $G=2$ and $K=96$ in the formula $T G=K$ , we get;

$T(2)=96$

$T=48$

Thus, the time taken to put out the fire using 200 gallons of water is 48 minutes.

Hence, Option B is the correct answer.

5 0

3 years ago

What is 2 divided by 165?

Digiron [165]

Answer:0.0121212121

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers