PROBLEM I WITHOUT A CALCULATOR)

The path of a projectile launched from a 26-ft-tall tower is modeled by the equation y = −16t2 + 64t + 26. What is the maximum h

BabaBlast [244]

Answer:

The maximum height of the projectile is 90 ft

Step-by-step explanation:

Here, we want to get the maximum height reached by the projectile

The answer here will be the y-coordinate value of the vertex form of the given equation

so firstly, we have to write the equation in the vertex form

We have this as;

y = -16t^2 + 64t + 26

That will be;

y = a(x-h)^2 + k

y = -16(x-2)^2 + 90

where the vertex of the equation is;

(-h,k)

K

in this case is 90 and thus, that is the maximum height of the projectile

8 0

3 years ago

Help me solve this pls

ddd [48]

Answer:

$\frac{x - 10}{8}$

Step-by-step explanation:

$\frac{3x}{8} - \frac{x + 5}{4}$

The common denominator of both fractions is 8. Therefore,, divide the denominator of each fraction, then multiply what you get by the numerator of each fraction.

Thus:

$\frac{1(3x) - 2(x + 5)}{8}$

$\frac{3x - 2x - 10}{8}$

$\frac{x - 10}{8}$

5 0

3 years ago

Jay sells 10 packs of apples for 80p. He wants to make £75 at the end of the year. How many packs of apples does he need to sell

ipn [44]

Answer:

937.5 packs of apples

Step-by-step explanation:

Note that:

100p = £1

80p = x

Cross Multiply

100x = 80p × £1

x = 80/100

x = £0.8

Jay sells 10 packs of apples for 80p.

Hence:

£0.8 = 10 packs of apples

£75 = x

Cross Multiply

£0.8 × x = £75 × 10 Packs

x = £75 × 10 Packs/£0.8

x = 937.5

Therefore, to make £75 at the end of the year, he has to sell 937.5 packs of apples

3 0

2 years ago

Building A is 400 feet tall and Building B is 300 feet tall. Johnny is standing in between the two building. The angle of elevat

Free_Kalibri [48]

Answer:

389 feets apart

Step-by-step explanation:

Given that:

Building A

Height = 400feets

Angle of elevation = 70°

Building B:

Height = 300 feets

Angle of elevation = 52°

Distance from the foot of building A to where Jonny is standing = x (see attached picture)

Using trigonometry :

Tanθ = opposite / Adjacent

Tan 70 = 400/ x

2.7474774x = 400

x = 145.58809 feets

Distance from the foot of building B to where Jonny is standing = y (see attached picture)

Using trigonometry :

Tanθ = opposite / Adjacent

Tan 52 = 300/ y

1.2799416y = 300

y = 145.59

y = 234.38568 feets

x + y = distance between the two buildings

(145.58809 + 234.38568) feets

= 379.97377

= 380 feets apart

5 0

3 years ago

Could somebody help me with Geometry? THANKS!!!!!!!!!!!!!!!!!!!!!

Vedmedyk [2.9K]

I'll do problem 1 to get you started.

The answer to problem 1 is <u>3400 miles</u>

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Explanation for problem 1:

We're asked to find the perimeter, which is the total distance around the exterior or outside. In other words, we need to add up the four side lengths of this quadrilateral.

We'll need the distance formula to find the lengths of the slanted sides AB and BC

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Let's first find the length of segment AB

A = (x1,y1) = (0,0)

B = (x2,y2) = (400,300)

d = Length of AB

$d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(0-400)^2 + (0-300)^2}\\\\d = \sqrt{(-400)^2 + (-300)^2}\\\\d = \sqrt{160000 + 90000}\\\\d = \sqrt{250000}\\\\d = 500\\\\$

The distance from A to B is 500 miles. This is the same as saying segment AB is 500 miles long.

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Now find the length of segment BC

B = (x1,y1) = (400,300)

C = (x2,y2) = (-800,800)

d = length of BC

$d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(400-(-800))^2 + (300-800)^2}\\\\d = \sqrt{(400+800)^2 + (300-800)^2}\\\\d = \sqrt{(1200)^2 + (-500)^2}\\\\d = \sqrt{1440000 + 250000}\\\\d = \sqrt{1690000}\\\\d = 1300\\\\$

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The length of CD is fairly easy to find without needing the distance formula. This is because it is a vertical line. We subtract the y coordinates of C and D to get 800-0 = 800. So CD is 800 miles long.

Segment DA is a similar story. But we subtract the x coordinates. This only works for horizontal lines. DA is 800 miles long because |-800-0| = 800. Absolute value is used to make sure the distance is never negative.

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To summarize everything so far, we found these four side lengths

AB = 500
BC = 1300
CD = 800
DA = 800

The perimeter is going to be the sum of those four sides, leading to...

perimeter = sum of sides

perimeter = AB+BC+CD+DA

perimeter = 500+1300+800+800

perimeter = 3400 miles

This is the total distance traveled if you started at city A, went to B, then to C, then to D, and then finally went back to A.

5 0

3 years ago

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