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3 years ago

Please answer the question above

Mathematics

1 answer:

bonufazy [111]3 years ago

6 0

Answer:

i cant really see the question but ill guess 4 or 4.065

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what digit is in the ten thousands place 1.03098 which is the correct answer I know it's one of the zeros I believe which one is

elena-14-01-66 [18.8K]

Hello there

Actually, the correct answer is the 9

the first 0 is in the tenths spot, the 3 is in the hundredths, the second zero is in the thousandths, and the 9 is in the ten thousandths, while the 8 is in the hundred thousandths.

Therefore, the 9 is in the ten thousandths place

I hope this helped ^^

4 0

3 years ago

If angle 5 is 120 degrees, what is the measure of angle 6? Why?

Sliva [168]

Answer:the measure of angle 6 is 60 degrees.

Step-by-step explanation:

The two horizontal lines ate straight and parallel lines. It is established that the sum of the angles on a straight line is 180 degrees. Looking at the given figure, angle 5 and angle 6 are on a straight line. Therefore

Angle 5 + angle 6 = 180 degrees. Therefore,If angle 5 is 120 degrees,then

Angle 6 + 120 = 180

Angle 6 = 180 - 120 = 60 degrees.

4 0

3 years ago

Read 2 more answers

determine if l || m based on the information given on the diagram. If yes, state the converse that proves the lines are parallel

kirza4 [7]

Answer/Step-by-step explanation:

1. YES.

Converse: If same side interior angles are supplementary, then l || m. (Same side interior angles)

Since the sum of the two same side interior angles, 65° and 115°, equals 180°, therefore, l || m.

2. YES.

Converse: if two angles angles are a linear pair, they are supplementary, therefore l || m. (Linear pair)

Thus,

128° + 53° = 180°.

3. YES.

Converse: if two angles are corresponding angles and congruent, therefore l || m. (Corresponding angles).

Thus,

The indicated angles which are equal to 90°, are corresponding angles therefore, l || m.

4. YES

Converse: if two alternate exterior angles are congruent, then l || m. (Alternate exterior angles)

Thus, the two exterior angles are congruent, therefore l || m.

4 0

3 years ago

50+30 x12 20 POINTS GUYS YESSSSSSSSSSSSSSSSSSSSSSS

daser333 [38]

Answer:

960

Step-by-step explanation:

50+30= 80

80x12=960

8 0

4 years ago

Read 2 more answers

The amount of pollutants that are found in waterways near large cities is normally distributed with mean 8.6 ppm and standard de

Setler79 [48]

We assume that question b is asking for the distribution of $\\ \overline{x}$ , that is, the distribution for the average amount of pollutants.

Answer:

a. The distribution of X is a normal distribution $\\ X \sim N(8.6, 1.3)$ .

b. The distribution for the average amount of pollutants is $\\ \overline{X} \sim N(8.6, \frac{1.3}{\sqrt{38}})$ .

c. $\\ P(z>-0.08) = 0.5319$ .

d. $\\ P(z>-0.47) = 0.6808$ .

e. We do not need to assume that the distribution from we take the sample is normal. We already know that the distribution for X is normally distributed. Moreover, the distribution for $\\ \overline{X}$ is also normal because the sample was taken from a normal distribution.

f. $\\ IQR = 0.2868$ ppm. $\\ Q1 = 8.4566$ ppm and $\\ Q3 = 8.7434$ ppm.

Step-by-step explanation:

First, we have all this information from the question:

The random variable here, X, is the number of pollutants that are found in waterways near large cities.
This variable is normally distributed, with parameters:
$\\ \mu = 8.6$ ppm.
$\\ \sigma = 1.3$ ppm.
There is a sample of size, $\\ n = 38$ taken from this normal distribution.

a. What is the distribution of X?

The distribution of X is the normal (or Gaussian) distribution. X (uppercase) is the random variable, and follows a normal distribution with $\\ \mu = 8.6$ ppm and $\\ \sigma =1.3$ ppm or $\\ X \sim N(8.6, 1.3)$ .

b. What is the distribution of $\\ \overline{x}$ ?

The distribution for $\\ \overline{x}$ is $\\ N(\mu, \frac{\sigma}{\sqrt{n}})$ , i.e., the distribution for the sampling distribution of the means follows a normal distribution:

$\\ \overline{X} \sim N(8.6, \frac{1.3}{\sqrt{38}})$ .

c. What is the probability that one randomly selected city's waterway will have more than 8.5 ppm pollutants?

Notice that the question is asking for the random variable X (and not $\\ \overline{x}$ ). Then, we can use a standardized value or z-score so that we can consult the standard normal table.

$\\ z = \frac{x - \mu}{\sigma}$ [1]

x = 8.5 ppm and the question is about $\\ P(x>8.5)$ =?

Using [1]

$\\ z = \frac{8.5 - 8.6}{1.3}$

$\\ z = \frac{-0.1}{1.3}$

$\\ z = -0.07692 \approx -0.08$ (standard normal table has entries for two decimals places for z).

For $\\ z = -0.08$ , is $\\ P(z$ .

But, we are asked for $\\ P(z>-0.08) \approx P(x>8.5)$ .

$\\ P(z-0.08) = 1$

$\\ P(z>-0.08) = 1 - P(z$

$\\ P(z>-0.08) = 0.5319$

Thus, "the probability that one randomly selected city's waterway will have more than 8.5 ppm pollutants" is $\\ P(z>-0.08) = 0.5319$ .

d. For the 38 cities, find the probability that the average amount of pollutants is more than 8.5 ppm.

Or $\\ P(\overline{x} > 8.5)$ ppm?

This random variable follows a standardized random variable normally distributed, i.e. $\\ Z \sim N(0, 1)$ :

$\\ Z = \frac{\overline{X} - \mu}{\frac{\sigma}{\sqrt{n}}}$ [2]

$\\ z = \frac{\overline{8.5} - 8.6}{\frac{1.3}{\sqrt{38}}}$

$\\ z = \frac{-0.1}{0.21088}$

$\\ z = \frac{-0.1}{0.21088} \approx -0.47420 \approx -0.47$

$\\ P(z$

Again, we are asked for $\\ P(z>-0.47)$ , then

$\\ P(z>-0.47) = 1 - P(z$

$\\ P(z>-0.47) = 1 - 0.3192$

$\\ P(z>-0.47) = 0.6808$

Then, the probability that the average amount of pollutants is more than 8.5 ppm for the 38 cities is $\\ P(z>-0.47) = 0.6808$ .

e. For part d), is the assumption that the distribution is normal necessary?

For this question, we do not need to assume that the distribution from we take the sample is normal. We already know that the distribution for X is normally distributed. Moreover, the distribution for $\\ \overline{X}$ is also normal because the sample was taken from a normal distribution. Additionally, the sample size is large enough to show a bell-shaped distribution.

f. Find the IQR for the average of 38 cities.

We must find the first quartile (25th percentile), and the third quartile (75th percentile). For $\\ P(z$ , $\\ z \approx -0.68$ , then, using [2]: