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3 years ago

Please help me with this problem

Mathematics

1 answer:

tatyana61 [14]3 years ago

4 0

Sam sold half as many as Odel.
That means Odel sold twice as many as Sam.

Let x = number of pizzas sold by Sam.
Then Odel sold 2x.
Altogether they sold 126

x + 2x = 126

3x = 126

x = 42

Since x is the number of pizzas sold by Sam, that is our answer.

Answer: Sam sold 42 pizzas.

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Please help me :) once again

grigory [225]

Answer:

About 11.31 cm

Step-by-step explanation:

If one of the legs of a right iscosceles triangle is 8, then the length of the other one must also be 8. Therefore, by the Pythagorean Theorem:

$h=\sqrt{8^2+8^2}=\sqrt{64+64}=\sqrt{128}\approx11.31$

Hope this helps!

7 0

3 years ago

Read 2 more answers

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Charra [1.4K]

Answer:

5x 1/4

Step-by-step explanation:

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3 years ago

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What is the degree of this polynomial 15x^5z^2-7y

Tanya [424]

That polynomial is made up of 2 terms, $15 x^{5}z ^{2}$ and 7y, separated by a minus sign. To find the degree of a polynomial you consider the term with the highest degree, no matter that the variables are different. The degree on the first term is 5+2=7, whereas the degree on the second term is just 1. Since the degree of a polynomial is equal to the degree of the term that is highest, our degree is 7.

4 0

3 years ago

20 feet of ribbon, cutting ribbon into 7 1/2 inches or 6 3/4 inch lengths to make bracelets. Write an algebraic expression that

IRINA_888 [86]

<u>ANSWER: </u>

The algebraic expression for number of ribbons is $\frac{20 \text { feet }-\left\{\frac{20 \text { feet }}{x}\right\}}{x}$ and the algebraic expression for length of ribbon is $\frac{25 x}{3} \text { feet }$

<u>SOLUTION: </u>

Given, 20 feet of ribbon, cutting ribbon into $7\frac{1}{2}$ inches or $6\frac{3}{4}$ inch lengths to make bracelets.

Let us convert the mixed fraction to improper fractions.

$7 \frac{1}{2}=\frac{7 \times 2+1}{2}=\frac{15}{2} \text { and } 6 \frac{3}{4}=\frac{6 \times 4+3}{4}=\frac{27}{4}$

Let, the length of bracelets can be made be “x”

First we have to remove the excess length of ribbon and then we have to divide the remaining with length of bracelet we want.

$\text { number of ribbons }=\frac{\text { length of ribbon-excess ribbon.}}{\text {length of bracelet}}$

$\left.=\frac{20 \text { feet }-\left\{\frac{20 \text { feep }}{x}\right.}{x} \text { [we know that, }\{x\} \text { is fractional part of } x\right$ ]

So, the algebraic expression for number of ribbons is $\frac{20 \text { feet }-\left\{\frac{20 \text { feet }}{x}\right\}}{x}$

Now, let us find the algebraic expression for feet of ribbon to make 100 ribbons.

We have 100 bracelets of length x, then total length = 100 × x

length of ribbon = 100x inches

$\begin{array}{l}{=100 \mathrm{x} \times \frac{1}{12} \text { feet }} \\\\ {=\frac{25 x}{3} \text { feet }}\end{array}$

So, the algebraic expression for length of ribbon is $\frac{25 x}{3} \text { feet }$

Hence, the algebraic expression for number of ribbons is $\frac{20 \text { feet }-\left\{\frac{20 \text { feet }}{x}\right\}}{x}$ and the algebraic expression for length of ribbon is $\frac{25 x}{3} \text { feet }$

5 0

3 years ago

Jay, a freelance editor, charges the rates shown in the table below to edit manuscripts. The cost per page increases as the qual

bekas [8.4K]

Gonna do a little subbing here...

for 40 pgs of express proof reading....3 bucks per pg...c = 3
40(3) - 0.05(40(3)) = T
120 - 0.05(120) = T.....120 - 6 = T.....114 = T
so express proofreading cost 114

for 40 pgs of basic proof reading....c = 3.95
40(3.95) - 0.05(40(3.95) = T
158 - 0.05(158) = T....158 - 7.9 = T.....150.10
so basic proof reading costs 150.10

for 40 pgs of extended proof reading....c = 5
40(5) - 0.05(40(5) = T
200 - 0.05(200) = T....200 - 10 = 190
so extended proof reading is 190

no need to go further....the extended proof reading is gonna be ur answer...the best quality of editing that keeps it at 190

3 0

3 years ago