Solve the equation. If necessary, round your answer to the nearest tenth.

Mathematics

1 answer:

andrew-mc [135]4 years ago

4 0

3x^2 = 147
divide both sides by 3
x^2 = 49
x^2 -49 = 0
(x-7)(x+7) =0
so,, x = 7 , -7
the answer is B

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$N(s)= \frac{89s}{14+14( \frac{s}{17})^2 }
\\
\\N'(s)= (\frac{89s}{14+14( \frac{s}{17})^2 } )'= \frac{89\times 14(1+( \frac{s}{17})^2)-89s\times \frac{28}{17} }{14^2(1+( \frac{s}{17})^2)} 
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