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Flauer [41]
3 years ago
12

Options are 70 75 85 or 100

Mathematics
1 answer:
lyudmila [28]3 years ago
3 0
Check the picture below

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Subtract:<br> 3 3/5 -1 1/1<br> 1 1/10<br> 2 1/10<br> 2 1/5<br> 2 2/3
VARVARA [1.3K]

Step-by-step explanation:

3 3/5 - 1 1/10

3 6/10 - 1 1/10

2 2/10= 2 1/5 is the answer

5 0
3 years ago
Solve: 2 + = 2. Give solutions in interval [0, 2)
Dovator [93]
\because\cos 2x+\sin x=\sin 2x\because\sin 2x=2\sin xcosx\because\cos 2x=\cos ^2x-\sin ^2x

→ Substitute cos 2x and sin 2x by their expressions

\therefore\cos ^2x-\sin ^2+\sin x=2\sin x\cos x

→ Subtract both sides by sin x

\cos ^2x-\sin ^2x=2\sin xcosx-\sin x

→ Take sin x as a common factor in the right side

\therefore\cos ^2x-\sin ^2x=\sin x(2\cos x-1)

From the graph, the equation has 4 solutions, the intersection points between the 2 graphs

7 0
1 year ago
There are 2.54 centimeters in 1 inch. There are 100 centimeters in 1 meter.
alexgriva [62]

Answer:

the whole number is 1.09842519685

that is in meters

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
What is the following quotient? ^3 square root 60 over ^3 square root of 20
ohaa [14]
The answer is the first one
4 0
3 years ago
Read 2 more answers
Please help!!!!!!!!!!!!
podryga [215]

Given : Fix amount charges = $200.

Each month additional charge = $50.

Let us assume number of months are taken by x.

So, we can setup a function as

Total charge  = Fix charge + each month charge * number of months.

f(x)  = 200 + 50*x

Or f(x) = 200 +5x.

Where function f is the total charge of x number of months.

The values of x's represents domain and function value represents range.

According to problem, it is said " first three months".

So, we need to take number of months as x=0,1,2,3.

And we need to find values of function for those x values.

On plugging x=0,1,2 and 3 we would get

f(0) = 200 +5(0) = 200 +0 = 200.

f(1) = 200 +5(1) = 200 +50 = 250.

f(2) = 200 +5(2) = 200 +100 = 300.

f(3) = 200 +5(3) = 200 +150 = 350.

We got function values 200,250,300 and 350.

Therefore, with respect to the given situation, the domain of the funtion is

{0,1,2,3} and Range { 200,250,300, 350}.

6 0
3 years ago
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