Between which hours was the rate at which the rain fell greater than the rate at which the rain fell
1 answer:
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sinR =
noting that the sin ratio =
opposite to ∠P is QR and hypotenuse is PQ ( opposite right angle )
Well, remember we can't take the square root of a negative
so we see that we have
so find those values that take sqrt of a negative and restrict hem from the domain
anny value greater than 1 and less than -1
so domain is from -1 to 1, including those numbers
D=[-1,1]
a. D=[-1,1] or from -1 to 1 is domain
b. for a TI-84, go to y-editor then input
for y1
c. for a TI-84, click 2nd then window (gets to tbset) scrol down to set Δx to 0.1, then cilick 2nd again then click graph (to select table) and scroll down till you see that value of y that is the biggest, that value is x=0.7
A. domain is from -1 to 1
B. use your brain or google the instructions for your calulator
C. at x=0.7
so we see that we have
so find those values that take sqrt of a negative and restrict hem from the domain
anny value greater than 1 and less than -1
so domain is from -1 to 1, including those numbers
D=[-1,1]
a. D=[-1,1] or from -1 to 1 is domain
b. for a TI-84, go to y-editor then input
c. for a TI-84, click 2nd then window (gets to tbset) scrol down to set Δx to 0.1, then cilick 2nd again then click graph (to select table) and scroll down till you see that value of y that is the biggest, that value is x=0.7
A. domain is from -1 to 1
B. use your brain or google the instructions for your calulator
C. at x=0.7