What is 10,000 more than 30,000+3,000+600+60+5

3. A savings account has a 3% interest rate. (a) Complete the ratio table shown. Show your work. Deposit ($) 100 50 300 Interest

Vladimir [108]

Answer:

Wait what

Step-by-step explanation:

6 0

3 years ago

Mike is reading a map with a scale of 1 in. = 35 mi. On the map, the

Umnica [9.8K]

Answer:

Actual distance represented by 5.5 inch of map distance is

$192.5$ miles

Step-by-step explanation:

Given,

The scale of map -

1 inch on map is equal to 35 miles.

Distance measured by mike on map is equal to 5.5 inch

Actual distance represented by 5.5 inch of map distance is

$= 5.5 * 35 = 192.5$ miles

8 0

3 years ago

Find the radius of the button. Please help I am stuck!

marysya [2.9K]

We can see that the diameter is 5 cm. Radius is simply half of the diameter.
5/2=2.5
The radius is 2.5 cm.

5 0

3 years ago

Read 2 more answers

Linear or non-linear?

Gnoma [55]

Answer:

the answer for this question is non-linear

Step-by-step explanation:

linear means in a straight line. the question you wrote is NOT in a strait line.

hoped the answer helped

7 0

3 years ago

HELP ASAP PLZZZZ

Tcecarenko [31]

QUESTION 1

The given system of equations is

$3d - e = 7...eqn(1)$
$d + e = 5...eqn(2)$

To solve by linear combination, we add equation (1) to equation (2) to get,

$3d + d= 7 + 5$

$4d = 12$

We divide through by 4 to obtain,

$d = \frac{12}{4}$

$d = 3$

We put d=3 into equation (2) to get,

$3+ e = 5$

$e = 5 - 3$

$e = 2$

$\boxed {The \: solution \: is \: (3, 2)}$

QUESTION 2

The given system is

4x + y = 5 ...eqn(1)

3x + y = 3 ...eqn(2)

To solve by linear combination, we subtract equation (2) from equation (1) to eliminate y from the equation.

This will give us,

$4x - 3x = 5 - 3$

This implies that,

$x = 2$

Put x=3 into equation (1) to get,

$4(2) + y = 5$

$8+ y = 5$

$y = 5 - 8$

$y = - 3$

The solution is

$(2,-3)$

QUESTION 3

We want to solve the system;

a – 2b = –2 ....eqn(1)

2a + 2b = 14...eqn(2)

by linear combination.

We need to add equation (1) to equation (2) to eliminate b.

This implies that,

$2a + a = 14 + - 2$

Simplify,

$3a = 12$

Divide both sides by 3 to get,

$a = 4$
Put a=4 into equation (2) to obtain,

$2(4) + 2b = 14$

$8 + 2b = 14$
$2b = 14 - 8$

$2b = 6$

$b = 3$

The ordered pair in the form (a, b) is

$(4,3)$

QUESTION 4

The given system of equations is

11x + 4y = 18 ...eqn(1)

3x + 4y = 2 ...eqn(2)

We subtract equation (2) from equation (1) to get,

$11x - 3x = 18 - 2$

$8x = 16$

$x = 2$

Put x=2 into equation (2) to obtain,

$3(2) + 4y = 2$

This implies that,

$6 + 4y = 2$

$4y = 2 - 6$

$4y = - 4$

$y=-1$

The correct answer is (2,-1).

QUESTION 5

The given system is ;

2d + e = 8...eqn1

d – e = 4...eqn2

We add the two equations to eliminate e.

This implies that,

$2d + d = 8 + 4$

$3d = 12$

We divide both sides by 3 to get,

$d = 4$

We put d=4 into equation (2) to get,

$4 - e = 4$

$- e = 4 - 4$

$- e = 0$

$e = 0$

The solution is

$(4,0)$

7 0

3 years ago