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Vesnalui [34]
3 years ago
8

The number 4129 is in the sequence calculate the number which comes immediately before 4129 in the sequence

Mathematics
1 answer:
steposvetlana [31]3 years ago
4 0

Answer:

The number 4129 is in the sequence calculate the number which comes immediately before 4129 in the sequence

Step-by-step explanation:

please tell me on this question

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Solve the inequality, then identify the graph of the<br> solution.<br> -3x-336
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Answer:

You can't "solve" it but you can simplify it. When I factored it, I got -3(x+112).

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A box contains two purple marbles nine orange marbles and seven yellow marbles if you pick two without looking what is the proba
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1/4

Step-by-step explanation:

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Write the expression in a standard equation form. \"eight times the difference of a number and three is sixty-four\"
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3 years ago
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The initial value of a quantity Q (at year t = 0) is 112.8 and the quantity is decreasing by 23.4% per year. a) Write a formula
Svetach [21]

Answer:

a) Q(t) = 112.8*(0.766)^{t}

b) When t = 10, Q = 7.845.

Step-by-step explanation:

The value of a quantity after t years is given by the following formula:

Q(t) = Q_{0}(1 + r)^{t}

In which Q_{0} is the initial quantity and r is the rate that it changes. If it increases, r is positive. If it decreases, r is negative.

a) Write a formula for Q as a function of t.

The initial value of a quantity Q (at year t = 0) is 112.8.

This means that Q_{0} = 112.8.

The quantity is decreasing by 23.4% per year.

This means that r = -0.234

So

Q(t) = 112.8*(1 - 0.234)^{t}

Q(t) = 112.8*(0.766)^{t}

b) What is the value of Q when t = 10?

This is Q(10).

Q(t) = 112.8*(0.766)^{t}

Q(t) = 112.8*(0.766)^{10} = 7.845

When t = 10, Q = 7.845.

4 0
4 years ago
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