Answer:
this is what i found
Factor
x out of x 2
. x
⋅ x
− 6
x Factor x out of −
6
x
. x
⋅
x +
x
⋅
−
6 Factor x out of x
⋅
x +
x
⋅
−
6
.
x
(
x
−
6 )
Answer:
Answer:
t ≅ 5.09 min
Step-by-step explanation:
we have that if in 4000 L/sol there is 132 kg salt and the pumping speed is 12L/s, we must find how much of salt is pumping per second and then find the amount of salt remaining
12L/s*132kg salt/4000L = 0.396 Kg salt/s, this means that 0.396 kg per second comes out , It should be found that the amount of salt must be drained so that only 11 kg of salt remain
132kg salt - 11 kg salt = 121 kg salt, so
121Kg salt*s/0.396Kg salt ≅ 305.55 s ⇒ 305.55s*min/60s ≅ 5.09 min
Step-by-step explanation:
Answer:
11 sq units
Step-by-step explanation:
(6×4) - ½(6×1 + 4×3 + 2×4)
= 24 - ½(6+12+8)
= 24 - ½(26)
= 24-13
= 11 sq units
Answer:
i think b
Step-by-step explanation:
Answer: I'm pretty sure that it´s C but Im not sure.
Sorry if that's wrong.