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2 years ago

7

The larger leg of a right triangle is 2 feet longer than its smaller leg. The hypotenuse is 4 feet longer than the smaller leg.

How many feet long is the larger leg?

1 answer:

maks197457 [2]2 years ago

7 0

Hope it helps you:))

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Joan has a prescription for 100 capsules.She only have enough money to pay for 1/4 of her prescription.How many capsules will Jo

CaHeK987 [17]

Answer:25

Step-by-step explanation:

100 divided by 4 equals 25

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2 years ago

Find the length of the third side to the nearest tenth.<br> Hurry need help asap!!

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Answer:

2.8

Step-by-step explanation:

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2 years ago

What is the mass (in grams) of 8.11×1026 CO2 molecules?

Kobotan [32]

Answer:

<u>It</u><u> </u><u>is</u><u> </u><u>5</u><u>9</u><u>,</u><u>2</u><u>7</u><u>5</u><u>.</u><u>7</u><u>4</u><u> </u><u>grams</u>

Step-by-step explanation:

• Molecular mass of carbon dioxide

$= (12 \times 1) + (16 \times 2) \\ = 12 + 32 \\ = 44 \: g$

[ molar masses: C = 12 g, O = 16 g ]

• From avogadro's number, it says 1 mole contains 6.02 × 10^23 molecules or atoms.

But 1 mole is equivalent to its molar mass in terms of weight, therefore;

${ \sf{6.02 \times {10}^{23} \: molecules = 44 \: g }}\\ { \sf{8.11 \times {10}^{26} \: molecules =( \frac{8.11 \times {10}^{26} }{6.02 \times {10}^{23} } \times 44) \: g}} \\ \\ = { \boxed{ \boxed{ \bf{59275.7 \: \: g}}}}$

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2 years ago

Height of the Qutab Minaar is 73 metre. When the last stone on the top of the Qutab Minaar was carried from ground to its top by

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peanut butter jelly sandwich

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2 years ago

Christine has always been weak in mathematics. Based on her performance prior to the final exam in Calculus, there is a 65% chan

amm1812

Answer:

0.49

Step-by-step explanation:

We apply conditional probability to solve this question.

We have Events X and Events Y

P(X) = Probability Christine fails the course = ??? Unknown

P(Y) = Probability Christine finds a tutor

= 0.35

P(Y') = Probability Christine does not find a tutor = 1 - 0.35 = 0.75

P(X|Y) = Decrease in her probability of failing = 0.35

P(X|Y') = Probability that she will fail the course if she does not have a tutor

P(X) = P(X|Y) × P(Y) + P(X|Y') × P(Y')

P(X) = 0.35 × 0.75 + 0.65 × 0.35

P(X) = 0.2625 + 0.2275

P(X) = 0.49

The probability that Christine fails the course is 0.49

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2 years ago