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3 years ago

PLZ HELP QUICK!! if you help i love you ❤️

Mathematics

1 answer:

horrorfan [7]3 years ago

4 0

You can’t even read the thing so how are we supposed to help?

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What is the input value for which f(x)=3

Zina [86]

Answer:

-3

Step-by-step explanation:

Because f(x) = y so when y=3 what is input value (x)

When y is 3 x is -3

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3 years ago

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Find the laplace transform of f(t) = cosh kt = (e kt + e −kt)/2

iren2701 [21]

Hello there, hope I can help!

I assume you mean $L\left\{\frac{ekt+e-kt}{2}\right\}$
With that, let's begin

$\frac{ekt+e-kt}{2}=\frac{ekt}{2}+\frac{e}{2}-\frac{kt}{2} \ \textgreater \ L\left\{\frac{ekt}{2}-\frac{kt}{2}+\frac{e}{2}\right\}$

$\mathrm{Use\:the\:linearity\:property\:of\:Laplace\:Transform}$
$\mathrm{For\:functions\:}f\left(t\right),\:g\left(t\right)\mathrm{\:and\:constants\:}a,\:b$
$L\left\{a\cdot f\left(t\right)+b\cdot g\left(t\right)\right\}=a\cdot L\left\{f\left(t\right)\right\}+b\cdot L\left\{g\left(t\right)\right\}$
$\frac{ek}{2}L\left\{t\right\}+L\left\{\frac{e}{2}\right\}-\frac{k}{2}L\left\{t\right\}$

$L\left\{t\right\} \ \textgreater \ \mathrm{Use\:Laplace\:Transform\:table}: \:L\left\{t\right\}=\frac{1}{s^2} \ \textgreater \ L\left\{t\right\}=\frac{1}{s^2}$

$L\left\{\frac{e}{2}\right\} \ \textgreater \ \mathrm{Use\:Laplace\:Transform\:table}: \:L\left\{a\right\}=\frac{a}{s} \ \textgreater \ L\left\{\frac{e}{2}\right\}=\frac{\frac{e}{2}}{s} \ \textgreater \ \frac{e}{2s}$

$\frac{ek}{2}\cdot \frac{1}{s^2}+\frac{e}{2s}-\frac{k}{2}\cdot \frac{1}{s^2}$

$\frac{ek}{2}\cdot \frac{1}{s^2} \ \textgreater \ \mathrm{Multiply\:fractions}: \frac{a}{b}\cdot \frac{c}{d}=\frac{a\:\cdot \:c}{b\:\cdot \:d} \ \textgreater \ \frac{ek\cdot \:1}{2s^2} \ \textgreater \ \mathrm{Apply\:rule}\:1\cdot \:a=a$
$\frac{ek}{2s^2}$

$\frac{k}{2}\cdot \frac{1}{s^2} \ \textgreater \ \mathrm{Multiply\:fractions}: \frac{a}{b}\cdot \frac{c}{d}=\frac{a\:\cdot \:c}{b\:\cdot \:d} \ \textgreater \ \frac{k\cdot \:1}{2s^2} \ \textgreater \ \mathrm{Apply\:rule}\:1\cdot \:a=a$
$\frac{k}{2s^2}$

$\frac{ek}{2s^2}+\frac{e}{2s}-\frac{k}{2s^2}$

Hope this helps!

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4 years ago

4 1/2 + 1 3/5 in simplest form

slavikrds [6]

The answer is 6.1 = 6 1/10

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3 years ago

Carlton is using the following data samples to make a claim about the house values in his neighborhood:

olga2289 [7]

The answer is A because there is a outlier which is $100,000

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Question 2 (1 point)

vagabundo [1.1K]

Answer:

See answers below

Step-by-step explanation:

For the expression

The sum of two numbers is 25. The first number is 37 more than 2 times the second number

Let the two numbers be x and y

If the sum is 25, then;

x + y = 25 .... 1

37 more than 2 times the second the number is expressed as;

37+2y

If the first number is 37 more than 2 times the second number, then;

x = 37 + 2y

x - 2y = 37 ...2

This shows that the simultaneous equation that fits the expressions are;

x - 2y = 37

x + y = 25

For the expression

A child has a piggy bank full of $1 and $2 coins totaling $37. There are 25 more $1 coins than there are $2 coins.

Let x be the $1 coins

Let y be the $2 coins

If a child has a piggy bank full of $1 and $2 coins totaling $37, then;

x + 2y = 37 ... 1

Also, if there are 25 more $1 coins than there are $2 coins, then;

x = 25 + y

x - y = 25 ...2

The equivalent expressions for the statement will be;

x + 2y = 37

x - y = 25

This hence leaves us with the last;

An exam that is worth 37 marks contain 25 questions. The questions are either worth 1 mark or 2 marks. The resulting simultaneous equation will be;

x + 2y = 37

x + y = 25

4 0

3 years ago