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Lelechka [254]
3 years ago
14

PLZ HELP QUICK!! if you help i love you ❤️

Mathematics
1 answer:
horrorfan [7]3 years ago
4 0
You can’t even read the thing so how are we supposed to help?
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What is the input value for which f(x)=3
Zina [86]

Answer:

-3

Step-by-step explanation:

Because f(x) = y so when y=3 what is input value (x)

When y is 3 x is -3

8 0
3 years ago
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Find the laplace transform of f(t) = cosh kt = (e kt + e −kt)/2
iren2701 [21]
Hello there, hope I can help!

I assume you mean L\left\{\frac{ekt+e-kt}{2}\right\}
With that, let's begin

\frac{ekt+e-kt}{2}=\frac{ekt}{2}+\frac{e}{2}-\frac{kt}{2} \ \textgreater \  L\left\{\frac{ekt}{2}-\frac{kt}{2}+\frac{e}{2}\right\}

\mathrm{Use\:the\:linearity\:property\:of\:Laplace\:Transform}
\mathrm{For\:functions\:}f\left(t\right),\:g\left(t\right)\mathrm{\:and\:constants\:}a,\:b
L\left\{a\cdot f\left(t\right)+b\cdot g\left(t\right)\right\}=a\cdot L\left\{f\left(t\right)\right\}+b\cdot L\left\{g\left(t\right)\right\}
\frac{ek}{2}L\left\{t\right\}+L\left\{\frac{e}{2}\right\}-\frac{k}{2}L\left\{t\right\}

L\left\{t\right\} \ \textgreater \  \mathrm{Use\:Laplace\:Transform\:table}: \:L\left\{t\right\}=\frac{1}{s^2} \ \textgreater \  L\left\{t\right\}=\frac{1}{s^2}

L\left\{\frac{e}{2}\right\} \ \textgreater \  \mathrm{Use\:Laplace\:Transform\:table}: \:L\left\{a\right\}=\frac{a}{s} \ \textgreater \  L\left\{\frac{e}{2}\right\}=\frac{\frac{e}{2}}{s} \ \textgreater \  \frac{e}{2s}

\frac{ek}{2}\cdot \frac{1}{s^2}+\frac{e}{2s}-\frac{k}{2}\cdot \frac{1}{s^2}

\frac{ek}{2}\cdot \frac{1}{s^2}  \ \textgreater \  \mathrm{Multiply\:fractions}: \frac{a}{b}\cdot \frac{c}{d}=\frac{a\:\cdot \:c}{b\:\cdot \:d} \ \textgreater \  \frac{ek\cdot \:1}{2s^2} \ \textgreater \  \mathrm{Apply\:rule}\:1\cdot \:a=a
\frac{ek}{2s^2}

\frac{k}{2}\cdot \frac{1}{s^2} \ \textgreater \  \mathrm{Multiply\:fractions}: \frac{a}{b}\cdot \frac{c}{d}=\frac{a\:\cdot \:c}{b\:\cdot \:d} \ \textgreater \  \frac{k\cdot \:1}{2s^2} \ \textgreater \  \mathrm{Apply\:rule}\:1\cdot \:a=a
\frac{k}{2s^2}

\frac{ek}{2s^2}+\frac{e}{2s}-\frac{k}{2s^2}

Hope this helps!
3 0
4 years ago
4 1/2 + 1 3/5<br><br>in simplest form​
slavikrds [6]
The answer is 6.1 = 6 1/10
7 0
3 years ago
Carlton is using the following data samples to make a claim about the house values in his neighborhood:
olga2289 [7]
The answer is A because there is a outlier which is $100,000
8 0
3 years ago
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Question 2 (1 point)
vagabundo [1.1K]

Answer:

See answers below

Step-by-step explanation:

For the expression

<em>The sum of two numbers is  25.  The first number is 37 more  than 2 times the second  number</em>

<em>Let the two numbers be x and y</em>

If the sum is 25, then;

x + y = 25 .... 1

37 more  than 2 times the second  the number is expressed as;

37+2y

If the first number is 37 more  than 2 times the second  number, then;

x = 37 + 2y

x - 2y = 37 ...2

<em>This shows that the simultaneous equation that fits the expressions are;</em>

x - 2y = 37

<em>x + y = 25</em>

<em>For the expression</em>

A child has a piggy bank full  of $1 and $2 coins totaling  $37.  There are 25 more $1 coins  than there are $2 coins.

Let x be the $1 coins

Let y be the $2 coins

<em>If a child has a piggy bank full  of $1 and $2 coins totaling  $37, then;</em>

x + 2y = 37 ... 1

<em>Also, if there are 25 more $1 coins  than there are $2 coins, then;</em>

x = 25 + y

x - y = 25 ...2

<em>The equivalent expressions for the statement will be;</em>

<em>x + 2y = 37</em>

<em>x - y = 25</em>

This hence leaves us with the last;

<em>An exam that is worth 37  marks contain 25  questions.  The questions are either  worth 1 mark or 2 marks. The resulting simultaneous equation will be;</em>

x + 2y = 37

x + y = 25

4 0
3 years ago
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